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Rxjava2 操作符 - Combining Observab

Rxjava2 操作符 - Combining Observab

作者: joker_fu | 来源:发表于2017-10-28 15:29 被阅读399次

    CombineLatest — 把两个Observable产生的结果进行合并,合并的结果组成一个新的Observable。最后一个Observable中的每一个数据项,都与前面Observable中的最后一项进行相应运算,将生成的结果组成一个新的Observable对象.。

        private static void andThenWhen() {
            Observable<Integer> o1 = Observable.just(1, 2, 3);
            Observable<Integer> o2 = Observable.just(4, 5, 6);
            Observable<Integer> o3 = Observable.just(7, 8, 9);
            Observable.combineLatest(o1, o2, o3, new Function3<Integer, Integer, Integer, String>() {
                @Override
                public String apply(@NonNull Integer integer, @NonNull Integer integer2, @NonNull Integer integer3) throws Exception {
                    return integer + " - " + integer2 + " - " + integer3;
                }
            }).subscribe(new Consumer<String>() {
                @Override
                public void accept(String string) throws Exception {
                    System.out.println("onNext: " + string);
                }
            });
    
        }
    }
    

    输出结果:

    onNext: 3 - 6 - 7
    onNext: 3 - 6 - 8
    onNext: 3 - 6 - 9

    Join —在另一个Observable发射的数据定义的时间窗口内,这个Observable发射了一条数据,就结合两个Observable发射的数据。

        private static void join() {
            Observable<Integer> o1 = Observable.just(1, 2, 3);
            Observable<Integer> o2 = Observable.just(4, 5, 6);
            Observable<Integer> o3 = Observable.just(7, 8, 9);
    
            o1.join(o2, new Function<Integer, ObservableSource<String>>() {
                @Override
                public ObservableSource<String> apply(@NonNull Integer integer) throws Exception {
                    return Observable.just(integer + "-o1").delay(200, TimeUnit.MILLISECONDS);
                }
            }, new Function<Integer, ObservableSource<String>>() {
                @Override
                public ObservableSource<String> apply(@NonNull Integer integer) throws Exception {
                    return Observable.just(integer + "-o2").delay(200, TimeUnit.MILLISECONDS);
                }
            }, new BiFunction<Integer, Integer, String>() {
                @Override
                public String apply(@NonNull Integer integer, @NonNull Integer integer2) throws Exception {
                    return integer + " - " + integer2;
                }
            }).subscribe(new Consumer<String>() {
                @Override
                public void accept(String s) throws Exception {
                    System.out.println("onNext" + s);
                }
            });
        }
    

    输出结果:

    onNext1 - 4
    onNext2 - 4
    onNext3 - 4
    onNext1 - 5
    onNext2 - 5
    onNext3 - 5
    onNext1 - 6
    onNext2 - 6
    onNext3 - 6

    Merge — 合并多个Observable为一个,可能会让合并的Observables发射的数据交错。

        private static void merge() {
            Observable<Integer> o1 = Observable.just(1, 2, 3);
            Observable<Integer> o2 = Observable.just(4, 5, 6);
            Observable.merge(o1, o2)
                    .subscribe(new Consumer<Integer>() {
                        @Override
                        public void accept(Integer integer) throws Exception {
                            System.out.println("onNext: " + integer);
                        }
                    });
        }
    

    输出结果:

    onNext: 1
    onNext: 2
    onNext: 3
    onNext: 4
    onNext: 5
    onNext: 6

    StartWith —一个Observable在发射源数据之前先发射一个指定的数据或数据序列

        private static void startWith() {
            Observable
                    .just(1, 2, 3)
                    .startWith(0)
                    .subscribe(new Consumer<Integer>() {
                        @Override
                        public void accept(Integer integer) throws Exception {
                            System.out.println("onNext: " + integer);
                        }
                    });
    
        }
    

    输出结果:

    onNext: 0
    onNext: 1
    onNext: 2
    onNext: 3

    Switch — switchOnNext操作符是把一组Observable转换成一个Observable,在同一个时间内存在两个或多个Observable提交的结果,只取最后一个Observable提交的结果给订阅者

        private static void rxSwitch() {
            Observable<Observable<Long>> o1 = Observable.interval(500, TimeUnit.MILLISECONDS)
                    .map(new Function<Long, Observable<Long>>() {
                        @Override
                        public Observable<Long> apply(@NonNull Long aLong) throws Exception {
                            return Observable.interval(200, TimeUnit.MILLISECONDS).map(new Function<Long, Long>() {
                                @Override
                                public Long apply(@NonNull Long aLong) throws Exception {
                                    return aLong * 10;
                                }
                            }).take(5);
                        }
                    })
                    .take(2);
            Observable
                    .switchOnNext(o1)
                    .subscribe(new Consumer<Long>() {
                        @Override
                        public void accept(Long aLong) throws Exception {
                            System.out.println("onNext:" + aLong);
                        }
                    });
            while (true);
        }
    

    输出结果:

    onNext:0
    onNext:10
    onNext:0
    onNext:10
    onNext:20
    onNext:30
    onNext:40

    Zip —把两个observable提交的结果,严格按照顺序进行合并

        private static void rxZip() {
            Observable
                    .zip(Observable.just(0, 1, 2), Observable.just("a", "b", "c"), new BiFunction<Integer, String, String>() {
                        @Override
                        public String apply(@NonNull Integer integer, @NonNull String s) throws Exception {
                            return "zip: " + 0 + " - " + s;
                        }
                    })
                    .subscribe(new Consumer<String>() {
                        @Override
                        public void accept(String s) throws Exception {
                            System.out.println(s);
                        }
                    });
        }
    

    输出结果:

    zip: 0 - a
    zip: 0 - b
    zip: 0 - c

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