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LeetCode387. First Unique Charac

LeetCode387. First Unique Charac

作者: Yuu_CX | 来源:发表于2016-11-19 20:39 被阅读0次

    Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1.
    Examples:
    s = "leetcode"return 0.s = "loveleetcode",return 2.
    Note: You may assume the string contain only lowercase letters.
    思路:若正向查找和反向查找字符的下标相同,则可返回第一个只出现了一次的字符。

    class Solution {
    public:
        int firstUniqChar(string s) {
            for(int i=0;i<s.size();i++){
                if(s.find(s[i])==s.rfind(s[i])) return i;
            }
            return -1;
        }
    };
    

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