create table default.score (
userid string,
monthid string,
score int
);
/*
insert into default.score values('001','01',70);
insert into default.score values('001','02',50);
insert into default.score values('001','03',60);
insert into default.score values('001','04',90);
insert into default.score values('001','05',70);
*/
--累计值写法一
select a.userid,a.monthid,a.score,sum(b.score)
from default.score a join default.score b on a.userid = b.userid
where a.monthid >= b.monthid
group by a.userid,a.monthid,a.score
order by a.userid,a.monthid;
--累计值写法二
select
userid,monthid,score,
sum(score) over(partition by userid order by monthid)
from default.score ;
--排名三种函数进行对比
--row_number
select userid
,monthid
,score
,row_number() over(order by score) as dense_number
from default.score;
--rank:
select userid
,monthid
,score
,rank() over(order by score) as rank
from default.score;
--dense_number
select userid
,monthid
,score
,dense_rank() over( order by score) as dense_number
from default.score;
--grouping sets
select userid
,monthid
,sum(score)
from default.score
group by userid,monthid
grouping sets ( (userid , monthid) ,(userid), (monthid));
--时间转换
select from_unixtime(unix_timestamp('20180905','yyyymmdd'),'yyyy-mm-dd');
select from_unixtime(unix_timestamp('2018-09-05','yyyy-mm-dd'),'yyyymmdd');
网友评论