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java 8 lambda表达式list操作分组、过滤、求和、最

java 8 lambda表达式list操作分组、过滤、求和、最

作者: 一个骚骚的码农 | 来源:发表于2021-12-07 10:58 被阅读0次

    java8的lambda表达式提供了一些方便list操作的方法,主要涵盖分组、过滤、求和、最值、排序、去重。跟之前的传统写法对比,能少写不少代码。

    新建实体类

    package com.vvvtimes.vo;

    import java.math.BigDecimal;
    import java.util.Date;

    public class User {

    private Long id;
    
    //姓名
    private String name;
    
    //年龄
    private int age;
    
    //工号
    private String jobNumber;
    
    //性别
    private String sex;
    
    //入职日期
    private Date entryDate;
    
    //家庭成员数量
    private BigDecimal familyMemberQuantity;
    
    public Long getId() {
        return id;
    }
    
    public void setId(Long id) {
        this.id = id;
    }
    
    public String getName() {
        return name;
    }
    
    public void setName(String name) {
        this.name = name;
    }
    
    public int getAge() {
        return age;
    }
    
    public void setAge(int age) {
        this.age = age;
    }
    
    public String getJobNumber() {
        return jobNumber;
    }
    
    public void setJobNumber(String jobNumber) {
        this.jobNumber = jobNumber;
    }
    
    public String getSex() {
        return sex;
    }
    
    public void setSex(String sex) {
        this.sex = sex;
    }
    
    public Date getEntryDate() {
        return entryDate;
    }
    
    public void setEntryDate(Date entryDate) {
        this.entryDate = entryDate;
    }
    
    public BigDecimal getFamilyMemberQuantity() {
        return familyMemberQuantity;
    }
    
    public void setFamilyMemberQuantity(BigDecimal familyMemberQuantity) {
        this.familyMemberQuantity = familyMemberQuantity;
    }
    

    }
    1.分组

    通过groupingBy可以分组指定字段

        //分组
        Map<String, List<User>> groupBySex = userList.stream().collect(Collectors.groupingBy(User::getSex));
        //遍历分组
        for (Map.Entry<String, List<User>> entryUser : groupBySex.entrySet()) {
            String key = entryUser.getKey();
            List<User> entryUserList = entryUser.getValue();
        }
    

    上门的分组存在key空值安全问题,需要做过滤或封装处理

    用Optional封装使用中会报No value present

    //分组添加累计
    Map<Optional<Long>, List<SalesOrderMonthlyStatementVo>> groupMap = list.stream().collect(Collectors.groupingBy(x -> Optional.ofNullable(x.getReviewerGroupId())));
    //遍历分组
    for (Map.Entry<Optional<Long>, List<SalesOrderMonthlyStatementVo>> entryGroup : groupMap.entrySet()) {
    Optional<Long> key = entryGroup.getKey();
    Long groupId = key.get();
    List<SalesOrderMonthlyStatementVo> entryGroupList = entryGroup.getValue();
    }
    正确使用方法如下,自定义groupingBy_WithNullKeys

    /** Like Collectors.groupingBy, but accepts null keys. */
    public static <T, A> Collector<T, ?, Map<A, List<T>>>
    groupingBy_WithNullKeys(Function<? super T, ? extends A> classifier) {
    return Collectors.toMap(
    classifier,
    Collections::singletonList,
    (List<T> oldList, List<T> newEl) -> {
    List<T> newList = new ArrayList<>(oldList.size() + 1);
    newList.addAll(oldList);
    newList.addAll(newEl);
    return newList;
    });
    }
    然后调用

    Map<Long, List<SalesOrderMonthlyStatementVo>> groupMap = list.stream().collect(groupingBy_WithNullKeys(x -> x.getReviewerGroupId()));
    多字段分组

        Function<WarehouseReceiptLineBatch, List<Object>> compositeKey = wlb ->
                Arrays.<Object>asList(wlb.getWarehouseReceiptLineId(), wlb.getWarehouseAreaId(), wlb.getWarehouseLocationId());
        Map<Object, List<WarehouseReceiptLineBatch>> map =
                warehouseReceiptLineBatchList.stream().collect(Collectors.groupingBy(compositeKey, Collectors.toList()));
        //遍历分组
        for (Map.Entry<Object, List<WarehouseReceiptLineBatch>> entryUser : map.entrySet()) {
            List<Object> key = (List<Object>) entryUser.getKey();
            List<WarehouseReceiptLineBatch> entryUserList = entryUser.getValue();
            Long warehouseReceiptLineId = (Long) key.get(0);
            Long warehouseAreaId = (Long) key.get(1);
            Long warehouseLocationId = (Long) key.get(2);
    
        }
    

    2.过滤

    通过filter方法可以过滤某些条件

        //过滤
        //排除掉工号为201901的用户
        List<User> userCommonList = userList.stream().filter(a -> !a.getJobNumber().equals("201901")).collect(Collectors.toList());
    

    3.求和

    分基本类型和大数类型求和,基本类型先mapToInt,然后调用sum方法,大数类型使用reduce调用BigDecimal::add方法

        //求和
        //基本类型
        int sumAge = userList.stream().mapToInt(User::getAge).sum();
        //BigDecimal求和
        BigDecimal totalQuantity = userList.stream().map(User::getFamilyMemberQuantity).reduce(BigDecimal.ZERO, BigDecimal::add);
    

    上面的求和不能过滤bigDecimal对象为null的情况,可能会报空指针,这种情况,我们可以用filter方法过滤,或者重写求和方法

    重写求和方法

    package com.vvvtimes.util;

    import java.math.BigDecimal;

    public class BigDecimalUtils {

    public static BigDecimal ifNullSet0(BigDecimal in) {
        if (in != null) {
            return in;
        }
        return BigDecimal.ZERO;
    }
    
    public static BigDecimal sum(BigDecimal ...in){
        BigDecimal result = BigDecimal.ZERO;
        for (int i = 0; i < in.length; i++){
            result = result.add(ifNullSet0(in[i]));
        }
        return result;
    }
    

    }
    使用重写的方法

    BigDecimal totalQuantity2 = userList.stream().map(User::getFamilyMemberQuantity).reduce(BigDecimal.ZERO, BigDecimalUtils::sum);
    判断对象空

    stream.filter(x -> x!=null)
    stream.filter(Objects::nonNull)
    判断字段空

    stream.filter(x -> x.getDateTime()!=null)
    4.最值

    求最小与最大,使用min max方法

        //最小
        Date minEntryDate = userList.stream().map(User::getEntryDate).min(Date::compareTo).get();
    
        //最大
        Date maxEntryDate = userList.stream().map(User::getEntryDate).max(Date::compareTo).get();
    

    有时候我们需要知道最大最小对应的这个对象,我们可以通过如下方法获取

    Comparator<LeasingBusinessContract> comparator = Comparator.comparing(LeasingBusinessContract::getLeaseEndDate);
    LeasingBusinessContract maxObject = leasingBusinessContractList.stream().max(comparator).get();
    5.List 转map

         /**
         * List -> Map
         * 需要注意的是:
         * toMap 如果集合对象有重复的key,会报错Duplicate key ....
         *  user1,user2的id都为1。
         *  可以用 (k1,k2)->k1 来设置,如果有重复的key,则保留key1,舍弃key2
         */
        Map<Long, User> userMap = userList.stream().collect(Collectors.toMap(User::getId, a -> a,(k1,k2)->k1));
    

    list转map的时候有时候会将date类型作为key,实际情况中使用string的多,我们可以将某个字段转成string

    Map<String, WorkCenterLoadVo> workCenterMap = list.stream().collect(Collectors.toMap(key->DateFormatUtils.format(key.getDate(), "yyyy-MM-dd"), a -> a,(k1,k2)->k1));
    list转map有时候会用到多字段key的map结构,除了常用的key用字符串连接,也可以使用apache commons的多字段key形式的map结构MultiKeyMap

    6.排序

    可通过Sort对单字段多字段排序

        //排序
        //单字段排序,根据id排序
        userList.sort(Comparator.comparing(User::getId));
        //多字段排序,根据id,年龄排序
        userList.sort(Comparator.comparing(User::getId).thenComparing(User::getAge));
    

    实际上这个写法存在空值安全问题,建议改成

    userList.sort(Comparator.comparing(User::getId,Comparator.nullsLast(Comparator.naturalOrder())).thenComparing(User::getAge,Comparator.nullsLast(Comparator.naturalOrder())));
    7.去重

    可通过distinct方法进行去重

        //去重
        List<Long> idList = new ArrayList<Long>();
        idList.add(1L);
        idList.add(1L);
        idList.add(2L);
        List<Long> distinctIdList = idList.stream().distinct().collect(Collectors.toList());
    

    针对属性去重

    List<AddOutboundNoticeDetailsBatchVo> entryDetailsBatchDistinctBatchIdList = entryDetailsBatchList.stream().filter(distinctByKey(b -> b.getMaterialBatchNumberId())).collect(Collectors.toList());

    //distinctByKey自己定义
    public static <T> Predicate<T> distinctByKey(Function<? super T, Object> keyExtractor) {
    Map<Object, Boolean> seen = new ConcurrentHashMap<>();
    return t -> seen.putIfAbsent(keyExtractor.apply(t), Boolean.TRUE) == null;
    }
    8.获取list某个字段组装新list

        //获取list对象的某个字段组装成新list
        List<Long> userIdList = userList.stream().map(a -> a.getId()).collect(Collectors.toList());
    

    9.批量设置list列表字段为同一个值

    addList.stream().forEach(a -> a.setDelFlag("0"));
    10.不同实体的list拷贝

    List<TimePeriodDate> timePeriodDateList1 = calendarModelVoList.stream().map(p->{TimePeriodDate e = new TimePeriodDate(); e.setStartDate(p.getBegin());e.setEndDate(p.getEnd()); return e;}).collect(Collectors.toList());

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