Socket封装包注意事项

null的ascii：<00> 一个ascii占一个字节

未理解
+ (int) nbyte2Int: (NSData *)nd
{
    //NSLog(@"[nbyte2Int] nd= %@", [NSString stringWithFormat:@"%@", nd]);
    // 测试：假设是00cc
    NSString *nstr = [[NSString stringWithFormat:@"%@", nd] substringWithRange:NSMakeRange(1, 4)];
    //NSLog(@"[nbyte2Int] str= %@", nstr);
    //========================= byte[] --> int =========================
    int len = [nstr length];
    int hc = 0;
    int int_ch = 0, z;
    for(int k=0; k<len; k++){
        hc = [nstr characterAtIndex:k];
        //NSLog(@"[nbyte2Int] hc= %d", hc);
        
        z = (len-1==k) ? 1 : (len-1-k)*16;
        if(hc >= '0' && hc <='9') { // 因为字符串'0'是十进制的48，
            int_ch += (hc-48)*z;
            NSLog(@"hc >= '0' && hc <='9'%c",hc);
        }else if(hc >= 'A' && hc <='F') { // 将 'A'~'F'的字符转化为10-15
            int_ch += (hc-55)*z;
            NSLog(@"hc >= 'A' && hc <='F'%c",hc);
        }else { // 将小写'a'~'f'转化为10 - 15
            int_ch += (hc-87)*z;
            NSLog(@"else%c",hc);
        }
        //NSLog(@"[nbyte2Int] int_ch= %d", int_ch);
        
    }
    //================================================================
    return int_ch;
}

如果socket是成功连接则无需再次注册，否则导致了（一直提示有人进入房间）

为什么重新初始化

屏幕快照 2018-12-25 下午9.23.31.png