HashMap

作者: zhi5ai | 来源:发表于2018-11-26 12:43 被阅读1次

HashMap是非线程安全的。也就是说,在多线程环境下,操作HashMap会导致各种各样的线程安全问题。比如说在HashMap扩容重哈希时出现的死循环问题,脏读问题等。

Java 7 的HashMap的源码,Java 8中这步已经简化了,只做了一次16位右位移异或混合,而不是四次。但原理未改变。

//java 7
static int hash(int h){
    h ^= (h >>> 20) ^ (h >>> 12);
    return h ^ (h >>> 7) ^ (h >>>4);
}
//Java 8中的散列值优化函数
static final int hash(Object key) {
        int h;
        return (key == null) ? 0 : (h = key.hashCode()) ^ (h >>> 16); //key.hashCode()为哈希算法,返回初始哈希值
// ^  位异或  >>> 无符号右移
    }
  • ==: 该操作符生成的是一个boolean结果,它计算的是操作数的值之间的关系。
  • equals: Object 的实例方法,比较两个对象的content是否相同
  • hashCode: Object 的native方法,获取对象的哈希值,用于确定该对象在哈希表中的索引位置,它实际上是一个int型整数。

HashMap实现原理

如果一个桶中的元素个数超过TREEIFY_THRESHOLD(默认是8),就使用红黑树来替换链表,从而提高速度。
这个替换的方法-treeifyBin()即树形化。

 /**
     * Replaces all linked nodes in bin at index for given hash unless
     * table is too small, in which case resizes instead.
     *将桶内所有的 链表节点 替换成 红黑树节点
     */
    final void treeifyBin(Node<K,V>[] tab, int hash) {
        int n, index; Node<K,V> e;
       //如果当前哈希表为空,或者哈希表中元素的个数小于 进行树形化的阀值(默认为64),就去新建/扩容
        if (tab == null || (n = tab.length) < MIN_TREEIFY_CAPACITY)
            resize();
        else if ((e = tab[index = (n - 1) & hash]) != null) {
       //如果哈希表中的元素个数超过了 树形化的阀值,进行树形化
      //e 是哈希表中指定位置桶里的链表节点,从第一个开始
            TreeNode<K,V> hd = null, tl = null; //红黑树的头,尾节点
            do {
                //新建一个树形节点,内容和当前链表节点 e 一致
                TreeNode<K,V> p = replacementTreeNode(e, null);
                if (tl == null)   //确定树头节点
                    hd = p;
                else {
                    p.prev = tl;
                    tl.next = p;
                }
                tl = p;
            } while ((e = e.next) != null);
           // 让桶里的第一个元素指向新建的红黑树头节点,以后这个桶里的元素就是红黑树而不是链表了
            if ((tab[index] = hd) != null)
                hd.treeify(tab);
        }
    }
//HashMap.class
static final class TreeNode<K,V> extends LinkedHashMap.LinkedHashMapEntry<K,V> {
      TreeNode<K,V> parent;  // red-black tree links
      TreeNode<K,V> left;
      TreeNode<K,V> right;
      TreeNode<K,V> prev;    // needed to unlink next upon deletion
      boolean red;
}

//LinkedHashMap.class
static class LinkedHashMapEntry<K,V> extends HashMap.Node<K,V> {
      LinkedHashMapEntry<K,V> before, after;
}

 /**HashMap.class
     * Basic hash bin node, used for most entries.  (See below for
     * TreeNode subclass, and in LinkedHashMap for its Entry subclass.)
     */
    static class Node<K,V> implements Map.Entry<K,V> {
        final int hash;
        final K key;
        V value;
        Node<K,V> next;
/**
         * Forms tree of the nodes linked from this node.
         * @return root of tree
         */
        final void treeify(Node<K,V>[] tab) {
            TreeNode<K,V> root = null;
            for (TreeNode<K,V> x = this, next; x != null; x = next) {
                next = (TreeNode<K,V>)x.next;
                x.left = x.right = null;
                if (root == null) {
                    x.parent = null;
                    x.red = false;
                    root = x;
                }
                else {
                    K k = x.key;
                    int h = x.hash;
                    Class<?> kc = null;
                    for (TreeNode<K,V> p = root;;) {
                        int dir, ph;
                        K pk = p.key;
                        if ((ph = p.hash) > h)
                            dir = -1;
                        else if (ph < h)
                            dir = 1;
                        else if ((kc == null &&
                                  (kc = comparableClassFor(k)) == null) ||
                                 (dir = compareComparables(kc, k, pk)) == 0)
                            dir = tieBreakOrder(k, pk);

                        TreeNode<K,V> xp = p;
                        if ((p = (dir <= 0) ? p.left : p.right) == null) {
                            x.parent = xp;
                            if (dir <= 0)
                                xp.left = x;
                            else
                                xp.right = x;
                            root = balanceInsertion(root, x);
                            break;
                        }
                    }
                }
            }
            moveRootToFront(tab, root);
        }

  /**
     * Initializes or doubles table size.  If null, allocates in
     * accord with initial capacity target held in field threshold.
     * Otherwise, because we are using power-of-two expansion, the
     * elements from each bin must either stay at same index, or move
     * with a power of two offset in the new table.
     *
     * @return the table
     */
    final Node<K,V>[] resize() {
        Node<K,V>[] oldTab = table;
        int oldCap = (oldTab == null) ? 0 : oldTab.length;
        int oldThr = threshold;
        int newCap, newThr = 0;
        if (oldCap > 0) {
            if (oldCap >= MAXIMUM_CAPACITY) {
                threshold = Integer.MAX_VALUE;
                return oldTab;
            }
            else if ((newCap = oldCap << 1) < MAXIMUM_CAPACITY &&
                     oldCap >= DEFAULT_INITIAL_CAPACITY)
                newThr = oldThr << 1; // double threshold
        }
        else if (oldThr > 0) // initial capacity was placed in threshold
            newCap = oldThr;
        else {               // zero initial threshold signifies using defaults
            newCap = DEFAULT_INITIAL_CAPACITY;
            newThr = (int)(DEFAULT_LOAD_FACTOR * DEFAULT_INITIAL_CAPACITY);
        }
        if (newThr == 0) {
            float ft = (float)newCap * loadFactor;
            newThr = (newCap < MAXIMUM_CAPACITY && ft < (float)MAXIMUM_CAPACITY ?
                      (int)ft : Integer.MAX_VALUE);
        }
        threshold = newThr;
        @SuppressWarnings({"rawtypes","unchecked"})
            Node<K,V>[] newTab = (Node<K,V>[])new Node[newCap];
        table = newTab;
        if (oldTab != null) {
            for (int j = 0; j < oldCap; ++j) {
                Node<K,V> e;
                if ((e = oldTab[j]) != null) {
                    oldTab[j] = null;
                    if (e.next == null)
                        newTab[e.hash & (newCap - 1)] = e;
                    else if (e instanceof TreeNode)
                        ((TreeNode<K,V>)e).split(this, newTab, j, oldCap);
                    else { // preserve order
                        Node<K,V> loHead = null, loTail = null;
                        Node<K,V> hiHead = null, hiTail = null;
                        Node<K,V> next;
                        do {
                            next = e.next;
                            if ((e.hash & oldCap) == 0) {
                                if (loTail == null)
                                    loHead = e;
                                else
                                    loTail.next = e;
                                loTail = e;
                            }
                            else {
                                if (hiTail == null)
                                    hiHead = e;
                                else
                                    hiTail.next = e;
                                hiTail = e;
                            }
                        } while ((e = next) != null);
                        if (loTail != null) {
                            loTail.next = null;
                            newTab[j] = loHead;
                        }
                        if (hiTail != null) {
                            hiTail.next = null;
                            newTab[j + oldCap] = hiHead;
                        }
                    }
                }
            }
        }
        return newTab;
    }

如果需要满足线程安全,可以用 Collections的synchronizedMap方法使HashMap具有线程安全的能力,或者使用ConcurrentHashMap。

ConcurrentHashMap 的实现原理

红黑树

Java7/8 中的HashMap 和 ConcurrentHashMap
算法导论-哈希表

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