拼接字符串
select concat('我叫', name, '我的性别:', sex) from user limit 1;
截取字符串
select substring("abcdefg", 1 , 3);
去除空格
select rtrim(name) from user where id =1;
select ltrim(name) from user where id =1;
select trim(name) from user where id =1;
mysql默认会把字符串和日期进行转换
DATE_FORMAT(CURRENT_DATE(), '%Y-%m-%d');
在emp表中,列出每年入职的人数和
select count(1), year(hiredate), max(sal) from emp group by year(hiredate);
创建视图,给别人用时可以隐藏emp里其他重要信息,只对外部分字段。可以简化查询语句
create view v_emp as select empno,ename,job from emp;
select * from v_emp;
insert into v_emp values(8888,'zs','clack');
查询工资比程序员低的人
select name, sal from emp where sal < all (select sal from emp where job = '程序员');
创建表成绩详情表:
CREATE TABLE score (
id int(10) NOT NULL AUTO_INCREMENT,
subject_id int(10) DEFAULT NULL,
student_id int(10) DEFAULT NULL,
score float DEFAULT NULL,
emp_max_count int(2) check(emp_max_count>0 and emp_max_count<20),
PRIMARY KEY (id)
) ENGINE=InnoDB AUTO_INCREMENT=19 DEFAULT CHARSET=utf8;
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屏幕快照 2018-05-22 下午1.21.42.png
创建学生表:
CREATE TABLE student (
id int(10) NOT NULL AUTO_INCREMENT,
name varchar(10) DEFAULT NULL,
PRIMARY KEY (id)
) ENGINE=InnoDB AUTO_INCREMENT=7 DEFAULT CHARSET=utf8;
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屏幕快照 2018-05-22 下午1.22.48.png
创建科目表:
CREATE TABLE subject (
id int(10) NOT NULL AUTO_INCREMENT,
name varchar(10) DEFAULT NULL,
PRIMARY KEY (id)
) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=utf8;
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屏幕快照 2018-05-22 下午1.23.39.png
select a.id,a.subject_id,a.student_id,a.score from score as a left join score as b on
a.subject_id=b.subject_id and a.score>=b.score
group by a.subject_id,a.student_id,a.score
having count(a.subject_id)>=4
order by a.subject_id,a.score desc;
SELECT c.* , tbt.num '班级人数' FROM class c
LEFT JOIN (SELECT count(sid) num , cname FROM student GROUP BY cname HAVING count(sid) > 30 ) tbt
WHERE c.cname = tbt.cname ;
数据库有2张表,一张学生表,一张成绩表,查询某学生的成绩,sql语言怎么写?
根据2张表关联的字段查询,比如学生表有学生ID字段,成绩表如果也有这个ID,则
select * from student inner join score on student.ID=score.学生ID
1.学生表
CREATE TABLE `Student` (
`sid` int(32) NOT NULL AUTO_INCREMENT,
`sname` varchar(32) DEFAULT NULL,
`ssox` varchar(32) DEFAULT NULL,
`sbirth` date DEFAULT NULL,
PRIMARY KEY (`sid`)
)
2.选课表
CREATE TABLE `selectCourse` (
`sid` int(32) DEFAULT NULL,
`cid` int(32) DEFAULT NULL
)
3.课程表
CREATE TABLE `Course` (
`cid` int(32) NOT NULL AUTO_INCREMENT,
`cname` varchar(32) DEFAULT NULL,
`cteacher` varchar(32) DEFAULT NULL,
PRIMARY KEY (`cid`)
)
INSERT INTO `Student` (`sid`, `sname`, `ssox`, `sbirth`) VALUES ('1', '神奇的我', '男', '1999-1-1');
INSERT INTO `Student` (`sid`, `sname`, `ssox`, `sbirth`) VALUES ('2', '神奇的他', '女', '1999-9-9');
INSERT INTO `Student` (`sid`, `sname`, `ssox`, `sbirth`) VALUES ('3', '老王', '男', '2000-12-12');
INSERT INTO `Student` (`sid`, `sname`, `ssox`, `sbirth`) VALUES ('4', '老张', '男', '2000-11-11');
INSERT INTO `Student` (`sid`, `sname`, `ssox`, `sbirth`) VALUES ('5', '小美', '女', '2001-1-1');
INSERT INTO `Student` (`sid`, `sname`, `ssox`, `sbirth`) VALUES ('6', '小明', '男', '2010-3-2');
INSERT INTO `Student` (`sid`, `sname`, `ssox`, `sbirth`) VALUES ('7', '小张', '男', '2012-12-12');
INSERT INTO `Course` (`cid`, `cname`, `cteacher`) VALUES ('1', '数学', '隔壁老王');
INSERT INTO `Course` (`cid`, `cname`, `cteacher`) VALUES ('2', '英语', '隔壁老张');
INSERT INTO `Course` (`cid`, `cname`, `cteacher`) VALUES ('3', '体育', '隔壁老王');
INSERT INTO `Course` (`cid`, `cname`, `cteacher`) VALUES ('4', '语文', '隔壁老李');
INSERT INTO `selectCourse` (`sid`, `cid`) VALUES ('1','1');
INSERT INTO `selectCourse` (`sid`, `cid`) VALUES ('1','2');
INSERT INTO `selectCourse` (`sid`, `cid`) VALUES ('1','3');
INSERT INTO `selectCourse` (`sid`, `cid`) VALUES ('2','1');
INSERT INTO `selectCourse` (`sid`, `cid`) VALUES ('2','2');
INSERT INTO `selectCourse` (`sid`, `cid`) VALUES ('2','3');
INSERT INTO `selectCourse` (`sid`, `cid`) VALUES ('3','2');
INSERT INTO `selectCourse` (`sid`, `cid`) VALUES ('4','2');
INSERT INTO `selectCourse` (`sid`, `cid`) VALUES ('5','2');
INSERT INTO `selectCourse` (`sid`, `cid`) VALUES ('6','2');
INSERT INTO `selectCourse` (`sid`, `cid`) VALUES ('7','2');
例如查询学生学号为1学生的有 哪些课程 分别什么老师
select cname,cteacher from Course inner join selectCourse on selectCourse.cid=Course.cid and sid=1;
例如查询老师叫 隔壁老王的老师 体育课程的学生
意思是 选择学生姓名 来自 学生表 条件
(来自教师表 和 选课表 中 当选课表课程id=3 并且 教师表课程id=3 并且老师为 隔壁老王)
select sname from Student where sid in
(select sid from Course inner join selectCourse on selectCourse.cid=3 and Course.cid=3 and cteacher='隔壁老王');
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