re.findall()函数使用

re.findall(pattern, string, flags=0)

返回string中所有非重叠的匹配——字符串列表

Return all non-overlapping matches of pattern in string, as a list of strings. The string is scanned left-to-right, and matches are returned in the order found. If one or more groups are present in the pattern, return a list of groups; this will be a list of tuples if the pattern has more than one group. Empty matches are included in the result unless they touch the beginning of another match.

使用：

url_str = """{

        'keyword=AAAAAAE5%9C%9F1&select',

        'keyword=E5%A3%A4%E6%9C0&select',

        'keyword=%E6%9C%BA%E6%A2&select',

        'keyword=4%E6%88%C%BA%E6&select',

        }"""

pattern = re.compile(r"keyword=([^&]+)&select")

matches = re.findall(pattern, url_str)

# 下面一行效果同上面两行

# matches = re.compile(r"keyword=([^&]+)&select").findall(url_str)

结果：['AAAAAAE5%9C%9F1', 'E5%A3%A4%E6%9C0', '%E6%9C%BA%E6%A2', '4%E6%88%C%BA%E6']