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Sqlalchemy几种查询方式(转)

Sqlalchemy几种查询方式(转)

作者: Captain_tu | 来源:发表于2017-07-06 11:30 被阅读47次
    #简单查询
    print(session.query(User).all())
    print(session.query(User.name, User.fullname).all())
    print(session.query(User, User.name).all())
    
    #带条件查询
    print(session.query(User).filter_by(name='user1').all())
    print(session.query(User).filter(User.name == "user").all())
    print(session.query(User).filter(User.name.like("user%")).all())
    
    #多条件查询
    print(session.query(User).filter(and_(User.name.like("user%"), User.fullname.like("first%"))).all())
    print(session.query(User).filter(or_(User.name.like("user%"), User.password != None)).all())
    
    #sql过滤
    print(session.query(User).filter("id>:id").params(id=1).all())
    
    #关联查询 
    print(session.query(User, Address).filter(User.id == Address.user_id).all())
    print(session.query(User).join(User.addresses).all())
    print(session.query(User).outerjoin(User.addresses).all())
    
    #聚合查询
    print(session.query(User.name, func.count('*').label("user_count")).group_by(User.name).all())
    print(session.query(User.name, func.sum(User.id).label("user_id_sum")).group_by(User.name).all())
    
    #子查询
    stmt = session.query(Address.user_id,         func.count('*').label("address_count")).group_by(Address.user_id).subquery()
    print(session.query(User, stmt.c.address_count).outerjoin((stmt, User.id == stmt.c.user_id)).order_by(User.id).all())
    
    #exists
    print(session.query(User).filter(exists().where(Address.user_id == User.id)))
    print(session.query(User).filter(User.addresses.any()))
    
    #返回限制字段
    person = session.query(Person.name, Person.created_at,                     
             Person.updated_at).filter_by(name="zhongwei").order_by(            
             Person.created_at).first()
    
    #记录总数查询:
    from sqlalchemy import func
    # count User records, without
    # using a subquery.session.query(func.count(User.id))
    
    # return count of user "id" grouped
    # by "name"
    session.query(func.count(User.id)).group_by(User.name)
    from sqlalchemy import distinct
    # count distinct "name" values
    session.query(func.count(distinct(User.name)))

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