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LeetCode-21 - Merge Two Sorted L

LeetCode-21 - Merge Two Sorted L

作者: 空即是色即是色即是空 | 来源:发表于2017-12-04 10:49 被阅读17次

    Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.

    Example:

    Input: 1->2->4, 1->3->4
    Output: 1->1->2->3->4->4

    Solution

    • 同时遍历两个列表用while l1 or l2
    • 两个列表判空,分3中case, l1 and l2; l1; l2
    # Definition for singly-linked list.
    # class ListNode(object):
    #     def __init__(self, x):
    #         self.val = x
    #         self.next = None
    
    class Solution(object):
        def mergeTwoLists(self, l1, l2):
            """
            :type l1: ListNode
            :type l2: ListNode
            :rtype: ListNode
            """
            result = ListNode(0)
            node = result
            while l1 or l2:
                if l1 and l2:
                    if l1.val < l2.val:
                        node.next = ListNode(l1.val)
                        l1 = l1.next
                    else:
                        node.next = ListNode(l2.val)
                        l2 = l2.next
                elif l1:
                    node.next = ListNode(l1.val)
                    l1 = l1.next
                elif l2:
                    node.next = ListNode(l2.val)
                    l2 = l2.next
                node = node.next
            return result.next
    

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