Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
Example:
Input: 1->2->4, 1->3->4
Output: 1->1->2->3->4->4
Solution
- 同时遍历两个列表用
while l1 or l2
- 两个列表判空,分3中case,
l1 and l2; l1; l2
# Definition for singly-linked list.
# class ListNode(object):
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution(object):
def mergeTwoLists(self, l1, l2):
"""
:type l1: ListNode
:type l2: ListNode
:rtype: ListNode
"""
result = ListNode(0)
node = result
while l1 or l2:
if l1 and l2:
if l1.val < l2.val:
node.next = ListNode(l1.val)
l1 = l1.next
else:
node.next = ListNode(l2.val)
l2 = l2.next
elif l1:
node.next = ListNode(l1.val)
l1 = l1.next
elif l2:
node.next = ListNode(l2.val)
l2 = l2.next
node = node.next
return result.next
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