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RxSwift_v1.0笔记——9: Combining Ope

RxSwift_v1.0笔记——9: Combining Ope

作者: 大灰很 | 来源:发表于2017-07-11 08:44 被阅读69次

    Prefixing and concatenating

    startWith

    增加前缀。在发出事件消息之前,先发出某个特定的事件消息。


    startWith
    example(of: "startWith") {
      // 1
      let numbers = Observable.of(2, 3, 4)
    
      // 2
      let observable = numbers.startWith(1)
      observable.subscribe(onNext: { value in
        print(value)
      })
    }
    --- Example of: startWith ---
    1
    2
    3
    4
    

    concat

    会把多个sequence和并为一个sequence,并且当前面一个sequence发出了completed事件,才会开始下一个sequence的事件。在第一sequence完成之前,第二个sequence发出的事件都会被忽略,但会接收一完成之前的二发出的最后一个事件。
    下例中Observable直接完成了,所以相当于直接链接

    Observable.concat
    example(of: "Observable.concat") {
      // 1
      let first = Observable.of(1, 2, 3)
      let second = Observable.of(4, 5, 6)
    
      // 2
      let observable = Observable.concat([first, second])
    
      observable.subscribe(onNext: { value in
        print(value)
      })
    }
    --- Example of: Observable.concat ---
    1
    2
    3
    4
    5
    6
    

    concat(_:)

    an instance method of Observable, instead of a class method

    example(of: "concat") {
      let germanCities = Observable.of("Berlin", "Munich", "Frankfurt")
      let spanishCities = Observable.of("Madrid", "Barcelona", "Valencia")
    
      let observable = germanCities.concat(spanishCities)
      observable.subscribe(onNext: { value in
        print(value)
      })
    }
    --- Example of: concat ---
    Berlin
    Munich
    Frankfurt
    Madrid
    Barcelona
    Valencia
    

    concat one element

    同startWith(_:)

    example(of: "concat one element") {
      let numbers = Observable.of(2, 3, 4)
    
      let observable = Observable
        .just(1)
        .concat(numbers)
    
      observable.subscribe(onNext: { value in
        print(value)
      })
    }
    --- Example of: concat one element ---
    1
    2
    3
    4
    

    Merging

    merge

    合并两个Observable流合成单个Observable流,根据时间轴发出对应的事件


    merge
    example(of: "merge") {
      // 1
      let left = PublishSubject<String>()
      let right = PublishSubject<String>()
    
      // 2
      let source = Observable.of(left.asObservable(), right.asObservable())
    
      // 3
      let observable = source.merge()
      let disposable = observable.subscribe(onNext: { value in
        print(value)
      })
    
      // 4
      var leftValues = ["Berlin", "Munich", "Frankfurt"]
      var rightValues = ["Madrid", "Barcelona", "Valencia"]
    
      repeat {
        if arc4random_uniform(2) == 0 {
          if !leftValues.isEmpty {
            left.onNext("Left:  " + leftValues.removeFirst())
          }
        } else if !rightValues.isEmpty {
          right.onNext("Right: " + rightValues.removeFirst())
        }
      } while !leftValues.isEmpty || !rightValues.isEmpty
    
      // 5
      disposable.dispose()
    }
    --- Example of: merge ---
    Left:  Berlin
    Right: Madrid
    Left:  Munich
    Right: Barcelona
    Left:  Frankfurt
    Right: Valencia
    

    combineLatest

    绑定超过最多不超过8个的Observable流,结合在一起处理。和Zip不同的是combineLatest是一个流的事件对应另一个流的最新的事件,两个事件都会是最新的事件
    Every time one of the inner (combined) sequences emits a value, it calls a closure you provide. You receive the last value from each of the inner sequences.


    combineLatest
    example(of: "combineLatest") {
      let left = PublishSubject<String>()
      let right = PublishSubject<String>()
    
      // 1
      let observable = Observable.combineLatest(left, right, resultSelector: {
        lastLeft, lastRight in
        "\(lastLeft) \(lastRight)"
      })
      let disposable = observable.subscribe(onNext: { value in
        print(value)
      })
    
      // 2
      print("> Sending a value to Left")
      left.onNext("Hello,")
      print("> Sending a value to Right")
      right.onNext("world")
      print("> Sending another value to Right")
      right.onNext("RxSwift")
      print("> Sending another value to Left")
      left.onNext("Have a good day,")
    
      disposable.dispose()
    }
    --- Example of: combineLatest ---
    > Sending a value to Left
    > Sending a value to Right
    Hello, world
    > Sending another value to Right
    Hello, RxSwift
    > Sending another value to Left
    Have a good day, RxSwift
    

    combine user choice and value

    example(of: "combine user choice and value") {
      let choice : Observable<DateFormatter.Style> = Observable.of(.short, .long)
      let dates = Observable.of(Date())
    
      let observable = Observable.combineLatest(choice, dates) {
        (format, when) -> String in
        let formatter = DateFormatter()
        formatter.dateStyle = format
        return formatter.string(from: when)
      }
    
      observable.subscribe(onNext: { value in
        print(value)
      })
    }
    --- Example of: combine user choice and value ---
    7/11/17
    July 11, 2017
    

    zip

    绑定超过最多不超过8个的Observable流,结合在一起处理。注意Zip是一个事件对应另一个流一个事件。
    • Subscribed to the observables you provided.
    • Waited for each to emit a new value.
    • Called your closure with both new values.


    zip
    example(of: "zip") {
      enum Weather {
        case cloudy
        case sunny
      }
      let left: Observable<Weather> = Observable.of(.sunny, .cloudy, .cloudy, .sunny)
      let right = Observable.of("Lisbon", "Copenhagen", "London", "Madrid", "Vienna")
    
      let observable = Observable.zip(left, right) { weather, city in
        return "It's \(weather) in \(city)"
      }
      observable.subscribe(onNext: { value in
        print(value)
      })
    }
    --- Example of: zip ---
    It's sunny in Lisbon
    It's cloudy in Copenhagen
    It's cloudy in London
    It's sunny in Madrid
    

    Triggers

    withLatestFrom

    When button emits a value, ignore it but instead emit the latest value received from the simulated text field.

    withLatestFrom

    sample

    前面同withLatestFrom,只是点击时textfield没有更新值就不发出
    It does nearly the same thing with just one variation: each time the trigger observable emits a value, sample(:) emits the latest value from the “other” observable, but only if it arrived since the last “tick”. If no new data arrived, sample(:) won’t emit anything.

    sample
    example(of: "withLatestFrom") {
      // 1
      let button = PublishSubject<Void>()
      let textField = PublishSubject<String>()
    
      // 2
       let observable = button.withLatestFrom(textField)
    //  let observable = textField.sample(button)
      let disposable = observable.subscribe(onNext: { value in
        print(value)
      })
    
      // 3
      textField.onNext("Par")
      textField.onNext("Pari")
      textField.onNext("Paris")
      button.onNext()
      button.onNext()
    }
    --- Example of: withLatestFrom ---
    Paris
    Paris
    --- Example of: sample ---
    Paris
    

    Switches

    RxSwift comes with two main so-called “switching” operators: amb(_:) and switchLatest(). They both allow you to produce an observable sequence by switching between the events of the combined or source sequences. This allows you to decide which sequence's events will the subscriber receive at runtime.

    amb——ambiguous

    开始,你不知道要订阅谁。谁先发送,就取消另一个的订阅
    The amb(_:) operator subscribes to left and right observables. It waits for any of them to emit an element, then unsubscribes from the other one. After that, it only relays elements from the first active observable.


    amb
    example(of: "amb") {
      let left = PublishSubject<String>()
      let right = PublishSubject<String>()
    
      // 1
      let observable = left.amb(right)
      let disposable = observable.subscribe(onNext: { value in
        print(value)
      })
    
      // 2
      right.onNext("Copenhagen")
      left.onNext("Lisbon")
      left.onNext("London")
      left.onNext("Madrid")
      right.onNext("Vienna")
    
      disposable.dispose()
    }
    --- Example of: amb ---
    Copenhagen
    Vienna
    

    switchLatest

    可以对事件流进行转换,本来监听的subject1,我可以通过更改variable里面的value更换事件源。变成监听subject2了


    switchLatest
    example(of: "switchLatest") {
      // 1
      let one = PublishSubject<String>()
      let two = PublishSubject<String>()
      let three = PublishSubject<String>()
    
      let source = PublishSubject<Observable<String>>()
    
      // 2
      let observable = source.switchLatest()
      let disposable = observable.subscribe(onNext: { value in
        print(value)
      })
    
      // 3
      source.onNext(one)
      one.onNext("Some text from sequence one")
      two.onNext("Some text from sequence two")
    
      source.onNext(two)
      two.onNext("More text from sequence two")
      one.onNext("and also from sequence one")
    
      source.onNext(three)
      two.onNext("Why don't you seem me?")
      one.onNext("I'm alone, help me")
      three.onNext("Hey it's three. I win.")
    
      source.onNext(one)
      one.onNext("Nope. It's me, one!")
    
      disposable.dispose()
    }
    --- Example of: switchLatest ---
    Some text from sequence one
    More text from sequence two
    Hey it's three. I win.
    Nope. It's me, one!
    

    Combining elements within a sequence

    reduce

    只有在observable completes时,才发出值
    This is much like what you’d do with Swift collections, but with observable sequences.
    reduce(::) produces its summary (accumulated) value only when the
    source observable completes.

    reduce
    example(of: "reduce") {
      let source = Observable.of(1, 3, 5, 7, 9)
    
      // 1
      // 1
      let observable = source.reduce(0, accumulator: { summary, newValue in
        return summary + newValue
      })
    
      observable.subscribe(onNext: { value in
        print(value)
      })
    }
    --- Example of: reduce ---
    25
    

    scan

    You get one output value per input value. As you may have guessed, this value is the running total accumulated by the closure.

    scan
    example(of: "scan") {
      let source = Observable.of(1, 3, 5, 7, 9)
    
      let observable = source.scan(0, accumulator: +)
      observable.subscribe(onNext: { value in
        print(value)
      })
    }
    --- Example of: scan ---
    1
    4
    9
    16
    

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      网友评论

      • b59457960ac9:PublishSubject<String>()是不是不用调用asObservable, variable才需要?
        大灰很:@Twistar variable是必须调用asObservable,其他的都是可调可不调。可调可不调的我也没搞清楚
        b59457960ac9:@大灰很 example(of: "merge") {
        // 1
        let left = PublishSubject<String>()
        let right = PublishSubject<String>()

        // 2
        let source = Observable.of(left.asObservable(), right.asObservable())

        你上面的代码,这里调用了 asObservable()是正确的还是手误?
        大灰很:@Twistar 是的

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