group by后，记录id 最大值最小值，两个最值不一样就是重复邮箱
select email from ((select min(id) as minid,max(id) as maxid, email
from person group by email) as newPerson) where minid != maxid
#select Email from Person group by Email having count(*)>1;
#select sum(id/id) email from person group by email
# 利用count(*)计数
select email from person group by email having count(*)>1
D80 182. Duplicate Emails 题目链接 182. Duplicate Emails 题目分析...
Delete Duplicate Emails Rising Temperature
ProblemWrite a SQL query to find all duplicate emails in ...
Write a SQL query to find all duplicate emails in a table...
Write a SQL query to find all duplicate emails in a table...
原题Duplicate Emails group by后，记录id 最大值最小值，两个最值不一样就是重复邮箱 利用...
196. Delete Duplicate Emails Description Write a SQL quer...
182. Duplicate Emails Description Write a SQL query to fi...
题目：196. Delete Duplicate Emails Write a SQL query to dele...
[https://leetcode.com/problems/delete-duplicate-emails/]M...
本文标题：Duplicate Emails
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