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python 数字转换为大写

python 数字转换为大写

作者: 隔壁小红馆 | 来源:发表于2020-08-25 09:19 被阅读0次

    在会计的时候,用到将数字转换为大写,也就是讲数字转为汉字

    class cnumber:
        cdict = {}
        gdict = {}
        xdict = {}
    
        def __init__(self):
            self.cdict = {1: u'', 2: u'拾', 3: u'佰', 4: u'仟'}
            self.xdict = {1: u'元', 2: u'万', 3: u'亿', 4: u'兆'}  # 数字标识符
            self.gdict = {0: u'零', 1: u'壹', 2: u'贰', 3: u'叁', 4: u'肆', 5: u'伍', 6: u'陆', 7: u'柒', 8: u'捌', 9: u'玖'}
    
        def csplit(self, cdata):  # 拆分函数,将整数字符串拆分成[亿,万,仟]的list
            g = len(cdata) % 4
            csdata = []
            lx = len(cdata) - 1
            if g > 0:
                csdata.append(cdata[0:g])
            k = g
            while k <= lx:
                csdata.append(cdata[k:k + 4])
                k += 4
            return csdata
    
        def cschange(self, cki):  # 对[亿,万,仟]的list中每个字符串分组进行大写化再合并
            lenki = len(cki)
            i = 0
            lk = lenki
            chk = u''
            for i in range(lenki):
                if int(cki[i]) == 0:
                    if i < lenki - 1:
                        if int(cki[i + 1]) != 0:
                            chk = chk + self.gdict[int(cki[i])]
                else:
                    chk = chk + self.gdict[int(cki[i])] + self.cdict[lk]
                lk -= 1
            return chk
    
        def cwchange(self, data):
            cdata = str(data).split('.')
            cki = cdata[0]
            if len(cdata) == 1:
                i = 0
                chk = u''
                cski = self.csplit(cki)  # 分解字符数组[亿,万,仟]三组List:['0000','0000','0000']
                ikl = len(cski)  # 获取拆分后的List长度
                # 大写合并
                for i in range(ikl):
                    if self.cschange(cski[i]) == '':  # 有可能一个字符串全是0的情况
                        chk = chk + self.cschange(cski[i])  # 此时不需要将数字标识符引入
                    else:
                        chk = chk + self.cschange(cski[i]) + self.xdict[ikl - i]  # 合并:前字符串大写+当前字符串大写+标识符
                chk = chk + u'整'
            else:
                i = 0
                chk = u''
                cski = self.csplit(cki)  # 分解字符数组[亿,万,仟]三组List:['0000','0000','0000']
                ikl = len(cski)  # 获取拆分后的List长度
                # 大写合并
                for i in range(ikl):
                    if self.cschange(cski[i]) == '':  # 有可能一个字符串全是0的情况
                        chk = chk + self.cschange(cski[i])  # 此时不需要将数字标识符引入
                    else:
                        chk = chk + self.cschange(cski[i]) + self.xdict[ikl - i]  # 合并:前字符串大写+当前字符串大写+标识符
                # 处理小数部分
                ckj = cdata[1]
                lenkj = len(ckj)
                if lenkj == 1:  # 若小数只有1位
                    if int(ckj[0]) == 0:
                        chk = chk + u'整'
                    else:
                        chk = chk + self.gdict[int(ckj[0])] + u'角整'
                else:  # 若小数有两位的四种情况
                    if int(ckj[0]) == 0 and int(ckj[1]) != 0:
                        chk = chk + u'零' + self.gdict[int(ckj[1])] + u'分'
                    elif int(ckj[0]) == 0 and int(ckj[1]) == 0:
                        chk = chk + u'整'
                    elif int(ckj[0]) != 0 and int(ckj[1]) != 0:
                        chk = chk + self.gdict[int(ckj[0])] + u'角' + self.gdict[int(ckj[1])] + u'分'
                    else:
                        chk = chk + self.gdict[int(ckj[0])] + u'角整'
            return chk
    
    if __name__ == '__main__':
        pt = cnumber()
        print(pt.cwchange('14524'))  # 壹万肆仟伍佰贰拾肆元整
    
    

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