ADS

作者: 王姚 | 来源:发表于2018-04-09 17:36 被阅读0次
    #define ads_point_set(from, to)       (*(to)= *(from), (to)[1]=(from)[1], (to)[2]=(from)[2])
    #define ads_name_set(from, to)        (*(to)= *(from), (to)[1]=(from)[1])
    #define ads_name_clear(name)          name[0] = name[1] = 0
    #define ads_name_nil(name)            (name[0] == 0 && name[1] == 0)
    #define ads_name_equal(name1, name2)  (name1[0]==name2[0] \
                                           && name1[1]==name2[1])
    

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