美文网首页
[golang] Blowfish算法的go实现

[golang] Blowfish算法的go实现

作者: king_wang | 来源:发表于2017-09-24 20:12 被阅读0次

    最近由于工作的需要,需要的实现一个go的Blowfish算法。其实go本身有一个加密算法库crypto,其中有Blowfish。但是该算法在很多细节上跟我的需求不同,导致最终加密结果千差万别。

    Blowfish算法

    BlowFish是对称加密算法的其中一种。在很多场景下,作为DES的替代出现。BlowFish并不是直接用我们指定的密钥对数据加密,而是先对密钥进行预处理,然后用处理的结果再对数据加密。解密过程同理。

    BlowFish算法内置两个源密钥:pbox和sbox,pbox18位数组,sbox4个256位数组组成。算法在加密解密时,根据两个盒子大量使用位移运算和逻辑位运算。具体的算法细节自行百度/谷歌,本文就不详述了。

    GO实现

    1. 生成pbox和sbox

    几个重要的变量声明

    var (
        Pencs string = "!!!这是一个18位长度的串!!!"
        Sencs string = "!!!这是一个1024位长度的串!!!"
    
        Penc []uint8 = []uint8(Pencs)
        Senc []uint8 = []uint8(Sencs)
    
        Pinit []uint32 = make([]uint32, len(Penc)*7/32)
        Sinit []uint32 = make([]uint32, len(Senc)*7/32)
    
        PPP  []uint32 = make([]uint32, 18)  //p盒子
        SSS0 []uint32 = make([]uint32, 256) //第一个盒子
        SSS1 []uint32 = make([]uint32, 256) //第二个盒子
        SSS2 []uint32 = make([]uint32, 256) //第三个盒子
        SSS3 []uint32 = make([]uint32, 256) //第四个盒子
    )
    

    生成pbox和sbox

    将2个盒子的源串Pencs和Sencs,每个字节右移一定位数,生成中间数组Pinit和Sinit

    func initParam() {
        var poff int32 = 25
        plen := len(Penc)
        for i, j := 0, 0; j < plen; j++ {
            if j == plen-1 {
                Pinit[i] |= uint32(Penc[j]) >> uint32(-poff)
            } else if poff < 0 {
                Pinit[i] |= uint32(Penc[j]) >> uint32(-poff)
                i++
                poff += 32
                Pinit[i] |= uint32(Penc[j]) << uint32(poff)
            } else {
                Pinit[i] |= uint32(Penc[j]) << uint32(poff)
            }
            poff -= 7
        }
        var soff int32 = 25
        slen := len(Senc)
        for i, j := 0, 0; j < slen; j++ {
            if j == slen-1 {
                Sinit[i] |= uint32(Senc[j]) >> uint32(-soff)
            } else if soff < 0 {
                Sinit[i] |= uint32(Senc[j]) >> uint32(-soff)
                i++
                soff += 32
                Sinit[i] |= uint32(Senc[j]) << uint32(soff)
            } else {
                Sinit[i] |= uint32(Senc[j]) << uint32(soff)
            }
            soff -= 7
        }
    }
    
    2. 密钥预处理
    func SetKey(key []uint8) {
        ptemp := []uint32{0, 0}
        stemp := [][]uint32{SSS0, SSS1, SSS2, SSS3}
        copy(PPP, Pinit)
        for i, j := 0, 0; i < 4; i++ {
            copy(stemp[i], Sinit[j:])
            j += 256
        }
    
        lenth := len(key)
        ll := 0
        for i, j := uint32(0), uint32(0); i < 18; i++ {
            for k := 0; k < 4; k++ {
                ll %= lenth
                j = j<<8 | uint32(key[ll])&255
                ll++
            }
            PPP[i] ^= j
        }
        encryptKey(ptemp, 0, PPP, 0)
        for i := uint32(0); i < 16; i += 2 {
            encryptKey(PPP, i, PPP, i+2)
        }
        encryptKey(PPP, 16, stemp[0], 0)
        for j := uint32(2); j < 256; j += 2 {
            encryptKey(stemp[0], uint32(j-2), stemp[0], uint32(j))
        }
        k := 0
        l := 254
        for i := 1; i < 4; i++ {
            for j := 0; j < 256; j += 2 {
                encryptKey(stemp[k], uint32(l), stemp[i], uint32(j))
                k = i
                l = j
            }
        }
    }
    
    func encryptKey(in []uint32, inOff uint32, out []uint32, outOff uint32) {
        left := in[inOff] ^ PPP[0]
        inOff++
        right := in[inOff]
        for i := 0; i < 16; i++ {
            temp := (SSS0[left>>24&255] + SSS1[left>>16&255] ^ SSS2[left>>8&255]) + SSS3[left&255]
            i++
            right ^= temp ^ PPP[i]
            temp = (SSS0[right>>24&255] + SSS1[right>>16&255] ^ SSS2[right>>8&255]) + SSS3[right&255]
            left ^= temp ^ PPP[i+1]
        }
        out[outOff] = right ^ PPP[17]
        outOff++
        out[outOff] = left
    }
    
    3. 加密
    func Encrypt(encryptable []uint8) []uint8 {
        blocks := len(encryptable) / 64
        rem := len(encryptable) % 64
        length := blocks * 64
        var output []uint8
        if rem > 0 {
            output = make([]uint8, length+64)
        } else {
            output = make([]uint8, length)
        }
        for i := 0; i < 64-rem; i++ {
            encryptable = append(encryptable, 0)
        }
        for i := 0; i < len(encryptable); i += 8 {
            encryptBytes(encryptable, uint32(i), output, uint32(i))
        }
        return output
    }
    
    func encryptBytes(in []uint8, inOff uint32, out []uint8, outOff uint32) {
        left := ((uint32(in[inOff])&255)<<24 | (uint32(in[inOff+1])&255)<<16 | (uint32(in[inOff+2])&255)<<8 | (uint32(in[inOff+3]) & 255)) ^ PPP[0]
        right := (uint32(in[inOff+4])&255)<<24 | (uint32(in[inOff+5])&255)<<16 | (uint32(in[inOff+6])&255)<<8 | uint32(in[inOff+7])&255
        for i := 1; i < 17; i += 2 {
            right ^= (SSS0[left>>24&255] + SSS1[left>>16&255] ^ SSS2[left>>8&255]) + SSS3[left&255] ^ PPP[i]
            left ^= (SSS0[right>>24&255] + SSS1[right>>16&255] ^ SSS2[right>>8&255]) + SSS3[right&255] ^ PPP[i+1]
        }
        right ^= PPP[17]
        out[outOff] = uint8(right >> 24 & 255)
        out[outOff+1] = uint8(right >> 16 & 255)
        out[outOff+2] = uint8(right >> 8 & 255)
        out[outOff+3] = uint8(right & 255)
        out[outOff+4] = uint8(left >> 24 & 255)
        out[outOff+5] = uint8(left >> 16 & 255)
        out[outOff+6] = uint8(left >> 8 & 255)
        out[outOff+7] = uint8(left & 255)
    }
    

    相关文章

      网友评论

          本文标题:[golang] Blowfish算法的go实现

          本文链接:https://www.haomeiwen.com/subject/arclextx.html