嗯，再来刷一道，继续腾讯秋招的50题吧
https://leetcode-cn.com/problems/power-of-two/description/
这道题也是有比较tricky的方法了
python提供一个数字转成字符串的方法，bin
那么如果是2的幂的话，那么就应该只有1个1，这样思路就比较简单了呢
class Solution:
def isPowerOfTwo(self, n):
"""
:type n: int
:rtype: bool
"""
if n < 0:
return False
strNum = bin(n)
if strNum.count("1") == 1:
return True
else:
return False
嗯，再来刷一道，继续腾讯秋招的50题吧 https://leetcode-cn.com/problems/powe...
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本文标题：第二十七天 Power of Two
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