转自土土哥的博客,mark一下,方便以后查阅
只记录结论 分析过程略过
1.对于类,只要@implementation里实现了方法,不管@interface是否有声明,都可以返回methodSignature
2.对于Protocol声明的方法,不管实例方法还是类方法,不管required还是optional的,都可以返回methodSignature
// 模拟实现___methodDescriptionForSelector方法:
struct objc_method_description ttg_MethodDescription(Class class, SEL sel) {
// 结果
struct objc_method_description description = (struct objc_method_description){NULL, NULL};
Class currentClass = class;
while (currentClass && description.name == NULL) {
// 获取Protocol列表
unsigned int count = 0;
__unsafe_unretained Protocol **protocols = class_copyProtocolList(currentClass, &count);
// 遍历所有Protocol
for (unsigned int i = 0; i < count; i++) {
// Required 方法
description = protocol_getMethodDescription(protocols[i], sel, YES, class_isMetaClass(currentClass) ^ 1);
if (description.name != NULL) {
break;
}
// Optional 方法
description = protocol_getMethodDescription(protocols[i], sel, NO, class_isMetaClass(currentClass) ^ 1);
if (description.name != NULL) {
break;
}
}
// 释放
free(protocols);
// 找到、返回
if (description.name != NULL) {
return description;
}
// 获取父类,继续
currentClass = class_getSuperclass(currentClass);
}
// 获取实例方法
Method method = class_getInstanceMethod(class, sel);
if (method) {
// 找到实例方法
return *method_getDescription(method);
} else {
// 返回空
return (struct objc_method_description){NULL, NULL};
}
}
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