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判断字符串中是否包含emoji

判断字符串中是否包含emoji

作者: has | 来源:发表于2017-06-23 23:35 被阅读50次

    - (BOOL)isContainsEmoji:(NSString *)string {

    __block BOOL isEomji = NO;

    [string enumerateSubstringsInRange:NSMakeRange(0, [string length]) options:NSStringEnumerationByComposedCharacterSequences usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {

    const unichar hs = [substring characterAtIndex:0];

    // surrogate pair

    if (0xd800 <= hs && hs <= 0xdbff) {

    if (substring.length > 1) {

    const unichar ls = [substring characterAtIndex:1];

    const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;

    if (0x1d000 <= uc && uc <= 0x1f77f) {

    isEomji = YES;

    }

    }

    } else {

    // non surrogate

    if (0x2100 <= hs && hs <= 0x27ff && hs != 0x263b) {

    isEomji = YES;

    } else if (0x2B05 <= hs && hs <= 0x2b07) {

    isEomji = YES;

    } else if (0x2934 <= hs && hs <= 0x2935) {

    isEomji = YES;

    } else if (0x3297 <= hs && hs <= 0x3299) {

    isEomji = YES;

    } else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50|| hs == 0x231a ) {

    isEomji = YES;

    }

    if (!isEomji && substring.length > 1) {

    const unichar ls = [substring characterAtIndex:1];

    if (ls == 0x20e3) {

    isEomji = YES;

    }

    }

    }

    }];

    return isEomji;

    }

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