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2017-11-11

2017-11-11

作者: 神梦 | 来源:发表于2017-11-11 22:48 被阅读0次

    2017.11.11  靳艺伦【第一天】

    今天开始编写一个随机计算器程序。实现随机产生一个可以自己选择难度,并且可以统计做对题目数的随机计算。

    #include<iostream>

    #include<cmath>

    #include<ctime>

    using namespace std;

    static  int n=0, s=0;//用来统计算对的和算错的题目数量

    int random(int x)//定义一个可以生成随机数值的函数

    {

    int b, c;//b表示输出值,c作为一个中间变量,用于b的赋值

    c = pow(10, 5-x);

    b = rand() / c;//随机生成一个小于c的数

    return b;

    }

    void count(char sign,double shu1,double shu2)//定义一个计算器函数

    {

    double answer, test;

    switch(sign)

    {

    case'+':cout << shu1 << "+" << shu2 << "=?";

    cin >> answer;

    test = shu1 + shu2;

    if (test == answer)

        { cout << "You're right!" << endl; n = n + 1; }

    else cout << "You're wrong!" << endl;

    s = s + 1;

    break;

    case'-':cout << shu1 << "-" << shu2 << "=?";

    cin >> answer;

    test = shu1 - shu2;

    if (test == answer)

    {

    cout << "You're right!" << endl; n = n + 1;

    }

    else cout << "You're wrong!"<< endl;

    s = s + 1;

    break;

    case'*':cout << shu1 << "*" << shu2 << "=?";

    cin >> answer;

    test = shu1 *shu2;

    if (test == answer)

    {

    cout << "You're right!" << endl; n = n + 1;

    }

    else cout << "You're wrong!" << endl;

    s = s + 1;

    break;

    case'/':cout << shu1 << "/" << shu2 << "=?";

    //assert(shu2 != 0 && shu1 <shu2);

    cin >> answer;

    test = shu1/ shu2;

    if (test == answer)

    {

    cout << "You're right!" << endl; n = n + 1;

    }

    else cout << "You're wrong!" << endl;

    s = s + 1;

    break;

    }

    }

    int main()

    {

    int x;

    char sign;

    cout << "请选择难度1或2" << endl;

    cin >> x;

    cout << "请选择计算方法" << endl;

    cin >> sign;

    int shu1, shu2;

    do {srand(time(0));

    shu1 = random(x);

    srand(rand());

    shu2 = random(x);

    count(sign, shu1, shu2);

    cout << "算对的题数为" << n << '\t' << "算错的题数为" << s - n << endl;;

    system("pause");

    } while (s < 11);

    }

    明日计划:(I)对这个程序的部分不足进行改正:(1)修正除法时可能出现分母为0的情况(2)修正选择难度为2时可能出现难度1的题目的情况。

    (II)复习函数内容,开始学习数组

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