js校验身份证号

前端通常都是使用正则来校验嗷~有一次我前端放过去了结果被后台拦住了你说气不气？？
我把后台的java校验身份证方法拿过来转成了js~~~~
用了正则和其它的方法来校验身份证号的真伪

先讲一下身份证大概的。。那什么。。。。咋个说？颁发的规则？？
http://www.ip33.com/shenfenzheng.html
我的代码全部都参考👆这里的

上代码 👇

/**
 * 身份证校验
 * 返回出生日期、性别及年龄
 */
export function validateIdNumber(certNo) {
    let birthday = null;
    let sex = null;
    let age = -1;

    if (certNo.length != 15 && certNo.length != 18)
        return false;

    // 15位的全部或18位的前17位必须位数字
    let str = certNo.length === 15 ? certNo : certNo.substring(0, 17);
    let regNum = /^\d+$/;
    if (!regNum.test(str))
        return false;
    // 18位的最后一位可以是X或x
    let regLast = /[0-9Xx]/;
    let numLast = certNo.substring(17, 18);
    if (certNo.length === 18 && !regLast.test(numLast))
        return false;

    // 前两位对应的区位码
    let zoneArr = [11, 12, 13, 14, 15, 21, 22, 23, 31, 32, 33, 34, 35, 36, 37, 41, 42, 43, 44, 45, 46, 50, 51, 52, 53, 54, 61, 62, 63, 64, 65, 71, 81, 82, 91];
    if (zoneArr.indexOf(parseInt(certNo.substring(0, 2))) == -1)
        return false;

    // 校验年份、月份、日子
    let year = certNo.length === 15 ? `19${certNo.substring(6, 8)}` : certNo.substring(6, 10);
    let month = certNo.length === 15 ? certNo.substring(8, 10) : certNo.substring(10, 12);
    let day = certNo.length === 15 ? certNo.substring(10, 12) : certNo.substring(12, 14);
    let dayNum = parseInt(day);
    let monthNum = parseInt(month);
    let yearNum = parseInt(year);

    let currentYear = new Date().getFullYear();
    if (yearNum < 1900 || yearNum > currentYear)
        return false;
    if (monthNum > 12 || monthNum < 1)
        return false;

    if ((monthNum === 1 || monthNum === 3 || monthNum === 5 || monthNum === 7 || monthNum === 8 || monthNum === 10 || monthNum === 12) && dayNum > 31)
        return false;

    if ((monthNum === 4 || monthNum === 6 || monthNum === 9 || monthNum === 11) && dayNum > 30)
        return false;

    // 校验闰平年二月的天数
    if (monthNum === 2) {
        let leapYear = null;
        // 闰年
        if (yearNum % 4 === 0 && yearNum % 100 != 0)
            leapYear = dayNum > 29 ? false : true;
        else {// 平年
            leapYear = dayNum > 28 ? false : true;
        }
        if (!leapYear) {
            return false;
        }
    }
    // 上面这部分的代码语法用得太恶心了。。实不相瞒我转行来的，基础太差了正在补。。爸特它虽然恶心但好用哈哈哈哈哈

    birthday = `${year}-${month}-${day}`;
    age = currentYear - year;
    if (certNo.length === 18) {
        sex = certNo.substring(16, 17) % 2 === 0 ? '女' : '男';
    } else {
        sex = certNo.substring(13, 14) % 2 === 0 ? '女' : '男';
    }

    // 校验 校验码
    const powerList = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2];
    const paritybitList = ['1', '0', 'X', '9', '8', '7', '6', '5', '4', '3', '2'];
    let num = 0;
    let certArr = certNo.split('').map(Number).slice(0, 17);

    for (let i = 0; i < certArr.length; i++) {
        num += (certArr[i] * powerList[i]);
    }

    if (certNo[17] != paritybitList[num % 11]) {
        if (num%11 === 2) { 
            if(certNo[17] != 'x' && certNo[17] != 'X')
              return false;
         } else {
            return false;
        }
    }

    return {
        birthday,
        sex,
        age
    };
}

tada~~~_{一个相对较为完善的身份证校验方法就完成啦}~