1、将一个数组中的值从另一个包含这些值的数组中去掉

    var arr1 = [{ name: 'jk' }, { name: 'kjd' }, { name: 'ksj' }, { name: 'jh' }, { name: 'jjd' }, { name: 'js' }];

    var arr2 = [{ name: 'jk' }, { name: 'js' }];

    // 数组arr2中的对象完全包含在数组arr1中，那么怎么从arr1中将它们剔除呢？

    var obj1 = arr1.reduce(function (res, next) {

        return $.extend(res, { [next.name]: next });

    }, {}); // 转成对象

    for(item of arr2) {
        delete obj1[item.name]; // 从对象中删除属性
    }

    var arr3 = Object.keys(obj1).map(function(key) {
        return obj1[key];
    }); // 再转回数组

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2、分类对象

var objArr = [
{ name: 'wxm', fl: 'a' }, 
{ name: 'df', fl: 'c' }, 
{ name: 'vff', fl: 'd' }, 
{ name: 'edd', fl: 'b' },
{ name: 'wxm', fl: 'f' }, 
{ name: 'dss', fl: 'd' }, 
{ name: 'vd', fl: 'c' }, 
{ name: 'vfd', fl: 'a' },
{ name: 'hg', fl: 'd' }, 
{ name: 'wer', fl: 'e' },
{ name: 'wxm', fl: 'a' },
{ name: 'wdd', fl: 'f' }, 
{ name: 'wd', fl: 'g' },
{ name: 'hjg', fl: 'e' }];

var group = [
{ gr: ['a', 'c'] },
{ gr: ['b', 'f'] },
{ gr: ['d', 'g'] }, 
{ gr: ['e'] }];

要将objArr中的对象按照fl属性分成group中4组

var sort = group.map(function(item) {
        var gr = objArr.filter(function(perObj) {
            return item.gr.includes(perObj.fl);
        });
        return gr;
})
console.log(sort);

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