【Python｜Method】zip()

使用场景：

1.将两个或多个列表配对

names = ['a', 'b', 'c']

scores = [1, 2, 3]

zipped = zip(names, scores) # 这里打印出来是 <zip object at 0x10fae6940>

zipped_list = list(zipped) # 转换成list才能打印出来（或者使用 for 循环打印）

print(zipped_list)

2. 遍历多个可迭代对象

names = ['Alice', 'Bob', 'Charlie']

scores = [85, 90, 78]

for name, score in zip(names, scores):

  print(f"{name} scored {score}")

3. 并行处理多个列表

list1 = [1, 2, 3]

list2 = [4, 5, 6]

# 计算每对元素的和

sums = [x + y for x, y in zip(list1, list2)]

print(sums)

4. 创建字典

keys = ['name', 'age', 'city']

values = ['Alice', 30, 'New York']

# 创建字典

dictionary = dict(zip(keys, values))

print(dictionary)

5. 解压元组

pairs = [(1, 'a'), (2, 'b'), (3, 'c')]

# 解压元组

list1, list2 = zip(*pairs)

print(list1)

print(list2)

6. 构造矩阵

rows = [(1, 2, 3), (4, 5, 6), (7, 8, 9)]

# 转置矩阵

transposed = list(zip(*rows))

print(transposed)

7. 填充缺失值

from itertools import zip_longest

list1 = [1, 2, 3]

list2 = ['a', 'b']

# 使用 zip_longest 填充缺失值

zipped = list(zip_longest(list1, list2, fillvalue='N/A'))

print(zipped)

8. 组合数据进行处理

names = ['Alice', 'Bob']

ages = [25, 30]

cities = ['New York', 'Los Angeles']

# 组合并处理

for name, age, city in zip(names, ages, cities):

  print(f"{name}, {age} years old, lives in {city}")