throw异常处理抛出产生Debug Error,abort()

使用visual studio 2019写如下代码时

#include <iostream>

using namespace std;

int func1(int n);

int main()

{

int number;

cin >> number;

try { cout << func1(number) << endl; }

catch ( char* e)

{

cout << e << endl;

return 1;

}

}

int func1(int n)

{

int res = 1;

if (n < 0)

throw "error: n <0";

if (n == 0 || n == 1)

return 1;

while (n > 1)

{

res *= n;

n--;

}

return res;

}

理论上当n<0时，应为溢出计算范围，会抛出一个异常，但是产生如图错误

将代码改成如下，问题得以解决；

#include <iostream>

using namespace std;

int func1(int n);

int main()

{

int number;

cin >> number;

try { cout << func1(number) << endl; }

catch (const char* e)

{

cout << e << endl;

return 1;

}

}

int func1(int n)

{

int res = 1;

if (n < 0)

throw "error: n <0";

if (n == 0 || n == 1)

return 1;

while (n > 1)

{

res *= n;

n--;

}

return res;

}