Given an array consisting of n
integers, find the contiguous subarray of given length k
that has the maximum average value. And you need to output the maximum average value.
Example 1:
Input: [1,12,-5,-6,50,3], k = 4
Output: 12.75
Explanation: Maximum average is (12-5-6+50)/4 = 51/4 = 12.75
遍历数组,记录和的最大值。
代码如下:
class Solution {
public:
double findMaxAverage(vector<int>& nums, int k) {
long max = 0;
long sum = 0;
for(int i = 0; i < k; i++)
{
sum += nums[i];
}
max = sum;
for(int i = k; i < nums.size(); i++)
{
sum += nums[i];
sum -= nums[i - k];
if(sum > max)
max = sum;
}
return (double)max / k;
}
};
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