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LeetCode 58. Length of Last Word

LeetCode 58. Length of Last Word

作者: cb_guo | 来源:发表于2019-04-09 12:03 被阅读0次

    题目描述

    Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

    If the last word does not exist, return 0.

    Note: A word is defined as a character sequence consists of non-space characters only.

    Example:

    Input: "Hello World"
    Output: 5
    

    注意,不管最后多少个 ' ',都不算最后一个word,最后一个 word 是非 ' '

    Input: "Hello World  "
    Output: 5
    
    Input: "Hello World        "
    Output: 5
    

    题目思路

    • 思路一、
    class Solution {
    public:
        int lengthOfLastWord(string s) {
            int len = s.size();
            int result = 0;
            bool flag = false;
            
            for(int i=len-1; i >= 0; i--){
                if(s[i] == ' '){
                    if(flag == true){
                        break;
                    }
                    continue;
                }
                
                flag = true;
                result += 1;
            }
            return result;
        }
    };
    

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