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2.2.10数据类型String的常量池特性

2.2.10数据类型String的常量池特性

作者: 农家男孩 | 来源:发表于2017-07-05 22:05 被阅读0次
/**
 * @author wuyoushan
 * @date 2017/4/10.
 */
public class Service {
    public static void print(String stringParam){
        try{
            synchronized (stringParam) {
                while (true) {
                    System.out.println(Thread.currentThread().getName());
                    Thread.sleep(1000);
                }
            }
        }catch(InterruptedException e){
            e.printStackTrace();
        }
    }
}

/**
 * @author wuyoushan
 * @date 2017/4/4.
 */
public class ThreadA extends Thread{

    private Service service;

    public ThreadA(Service service) {
        this.service = service;
    }

    @Override
    public void run() {
       super.run();
        service.print("AA");
    }
}

/**
 * @author wuyoushan
 * @date 2017/4/4.
 */
public class ThreadB extends Thread{

   private Service service;

    public ThreadB(Service service) {
        this.service = service;
    }

    @Override
    public void run() {
        super.run();
        service.print("AA");
    }
}

/**
 * @author wuyoushan
 * @date 2017/3/20.
 */
public class Run {
    public static void main(String[] args){
      Service service=new Service();
      ThreadA a=new ThreadA(service);
      a.setName("A");
      a.start();
      ThreadB b=new ThreadB(service);
      b.setName("B");
      b.start();
    }
}

程序的运行结果为:

A
A
A
A

出现这样的情况就是因为String的两个值都是AA,两个线程持有相同的锁,所以造成线程B不能执行。这就是String常量池所带来的问题。因此在大多数情况下,同步synchronized代码块都不使用String作为锁对象,而改用其他,比如new Object()实例化一个Object对象,但它并不放入缓存中。

/**
 * @author wuyoushan
 * @date 2017/4/10.
 */
public class Service {
    public static void print(Object object){
        try{
            synchronized (object) {
                while (true) {
                    System.out.println(Thread.currentThread().getName());
                    Thread.sleep(1000);
                }
            }
        }catch(InterruptedException e){
            e.printStackTrace();
        }
    }
}

/**
 * @author wuyoushan
 * @date 2017/4/4.
 */
public class ThreadA extends Thread{

    private Service service;

    public ThreadA(Service service) {
        this.service = service;
    }

    @Override
    public void run() {
       super.run();
        service.print(new Object());
    }
}

/**
 * @author wuyoushan
 * @date 2017/4/4.
 */
public class ThreadB extends Thread{

   private Service service;

    public ThreadB(Service service) {
        this.service = service;
    }

    @Override
    public void run() {
        super.run();
        service.print(new Object());
    }
}

/**
 * @author wuyoushan
 * @date 2017/3/20.
 */
public class Run {
    public static void main(String[] args){
      Service service=new Service();
      ThreadA a=new ThreadA(service);
      a.setName("A");
      a.start();
      ThreadB b=new ThreadB(service);
      b.setName("B");
      b.start();
    }
}

程序的运行结果为:

A
B
A
B
B
A
B
A
B
A

交替打印的原因是持有的锁不是一个。

摘选自 java多线程核心编程技术-2.2.10

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