A binary watch has 4 LEDs on the top which represent the hours (0-11), and the 6 LEDs on the bottom represent the minutes (0-59).
Each LED represents a zero or one, with the least significant bit on the right.
imageFor example, the above binary watch reads "3:25".
Given a non-negative integer n which represents the number of LEDs that are currently on, return all possible times the watch could represent.
Example:
Input: n = 1
Return: ["1:00", "2:00", "4:00", "8:00", "0:01", "0:02", "0:04", "0:08", "0:16", "0:32"]
Note:
- The order of output does not matter.
- The hour must not contain a leading zero, for example "01:00" is not valid, it should be "1:00".
- The minute must be consist of two digits and may contain a leading zero, for example "10:2" is not valid, it should be "10:02".
一刷
题解:
最简单的做法:00:00-11:59遍历,然后用Integer.bitCount来计算满足要求的时间
class Solution {
public List<String> readBinaryWatch(int num) {
List<String> times = new ArrayList<>();
for(int h=0; h<12; h++){
for(int m = 0; m<60; m++){
if((Integer.bitCount(h) + Integer.bitCount(m)) == num){
if(m<10){
times.add(String.format("%d:0%d",h,m));
}else{
times.add(String.format("%d:%d",h,m));
}
}
}
}
return times;
}
}
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