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19. Remove Nth Node From End of

19. Remove Nth Node From End of

作者: a_void | 来源:发表于2016-09-26 21:55 被阅读0次

    Given a linked list, remove the nth node from the end of list and return its head.
    For example,

    Given linked list: **1->2->3->4->5**, and ***n* = 2**.
    After removing the second node from the end, 
    the linked list becomes **1->2->3->5**.
    

    Solution:

    /**
     * Definition for singly-linked list.
     * struct ListNode {
     *     int val;
     *     ListNode *next;
     *     ListNode(int x) : val(x), next(NULL) {}
     * };
     */
    class Solution {
    public:
        ListNode* removeNthFromEnd(ListNode* head, int n) {
            if(NULL == head) return head;
            int size = 0;
            for(ListNode* p = head;p!=NULL;p=p->next) size++;
            
            if(n == size) return head->next;
            
            ListNode *p = head;
            for(int i=0;i<size - n - 1;i++) p = p->next;
            p->next = p->next->next;
            return head;
        }
    };
    

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