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实战练习
在Jupyter Notebook上执行以下代码:
import pandas as pd
df = pd.DataFrame({'col1':[1,2,3,4],'col2':[444,555,666,444],'col3':['abc','def','ghi','xyz']})
df.head()
![](https://img.haomeiwen.com/i11678900/de43a09e7165475f.png)
获取唯一值
df['col2'].unique()
![](https://img.haomeiwen.com/i11678900/9a91f3e9b2986022.png)
获取非唯一值
df['col2'].nunique()
![](https://img.haomeiwen.com/i11678900/d9dcffebb300eeec.png)
获取每个值的个数
df['col2'].value_counts()
newdf = df[(df['col1']>2) & (df['col2']==444)]
newdf
![](https://img.haomeiwen.com/i11678900/7c5cdfe8462a57d3.png)
应用函数
def times2(x):
return x*2
df['col1'].apply(times2)
![](https://img.haomeiwen.com/i11678900/8deaef2a5f7e72bf.png)
df['col2'].apply(lambda x:x*2)
![](https://img.haomeiwen.com/i11678900/c7ec39ac61029ca2.png)
df['col3'].apply(len)
![](https://img.haomeiwen.com/i11678900/645d147758c43fc4.png)
df['col1'].sum()
![](https://img.haomeiwen.com/i11678900/481b33524bc80a30.png)
永久删除一列
del df['col1']
df
![](https://img.haomeiwen.com/i11678900/bd185b5f9968e005.png)
df = pd.DataFrame({'col1':[1,2,3,4],'col2':[444,555,666,444],'col3':['abc','def','ghi','xyz']})
df.drop('col1',axis=1,inplace=True)
df
![](https://img.haomeiwen.com/i11678900/015fdb9899c8015b.png)
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