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1. Two Sum

1. Two Sum

作者: april_mu | 来源:发表于2017-05-16 09:49 被阅读0次

    Given an array of integers, return indices of the two numbers such that they add up to a specific target.

    You may assume that each input would have exactly one solution, and you may not use the same element twice.

    Example:
    Given nums = [2, 7, 11, 15], target = 9,

    Because nums[0] + nums[1] = 2 + 7 = 9,
    return [0, 1].

    class Solution {
    public:
        vector<int> twoSum(vector<int>& nums, int target) {
            vector <int> answer;
            for (int i = 0; i< nums.capacity(); i++) {
                int adder = nums.at(i);
                for (int j = i + 1; j < nums.capacity(); j++) {
                    if (adder + nums.at(j) == target) {
                        answer.push_back(i);
                        answer.push_back(j);
                        break;
                    }
                }
            }
            return answer;
        }
    };
    

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