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剑指offer-顺时针打印矩阵

剑指offer-顺时针打印矩阵

作者: 纳萨利克 | 来源:发表于2019-10-04 10:29 被阅读0次

    输入一个矩阵,按照从外向里以顺时针的顺序依次打印出每一个数字,例如,如果输入如下4 X 4矩阵:
    1 2 3 4
    5 6 7 8
    9 10 11 12
    13 14 15 16
    则依次打印出数字
    1,2,3,4,
    8,12,16,15,
    14,13,9,5,
    6,7,11,10.

    思路
    使用up存储最上边行号,down存最下边行号,left存最左边列号,right存最右边列号
    将上方的值添加进list中,通过判断up>down结束,再将右边的值放入...

    Java

    import java.util.ArrayList;
    public class Solution {
      public ArrayList<Integer> printMatrix(int [][] matrix) {
        ArrayList<Integer> list = new ArrayList<>();
        if(matrix == null || matrix.length == 0 || matrix[0].length == 0) return list;
        
        int up = 0;
        int down = matrix.length-1;
        int left = 0;
        int right = matrix[0].length-1;
        
        while (true) {
          for (int col = left; col <= right; col++)
            list.add(matrix[up][col]);
          up++;
          if (up > down)  break;
          for (int row = up; row <= down; row++)
            list.add(matrix[row][right]);
          right--;
          if (right < left)  break;
          for (int col2 = right; col2 >= left; col2--)
            list.add(matrix[down][col2]);
          down--;
          if (up > down)  break;
          for (int row2 = down; row2 >= up; row2--)
            list.add(matrix[row2][left]);
          left++;
          if (right < left)  break;
        }
        return list;
      }
    }
    

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