美文网首页工作
使用mongoTemplate进行Aggregation聚合查询

使用mongoTemplate进行Aggregation聚合查询

作者: 李小二的倔强 | 来源:发表于2019-03-29 16:46 被阅读0次

    Aggregation聚合查询

    金山竹影几千秋,云索高飞水自流,万里长江飘玉带,一轮银月滚金球,远自湖北三千里,近到江南十六州,美景一时观不透,天缘有分画中游!

    需求:在订单表中,根据buyerNick分组,统计每个buyerNick的电话、地址、支付总金额以及总商品数,返回结果是CustomerDetail。

    /*
     * project:列出所有本次查询的字段,包括查询条件的字段和需要搜索的字段;
     * match:搜索条件criteria
     * unwind:某一个字段是集合,将该字段分解成数组
     * group:分组的字段,以及聚合相关查询
     *      sum:求和(同sql查询)
     *      count:数量(同sql查询)
     *      as:别名(同sql查询)
     *      addToSet:将符合的字段值添加到一个集合或数组中
     * sort:排序
     * skip&limit:分页查询
     */
    public List<CustomerDetail> customerDetailList(Integer pageNum,String userId,String buyerNick,String itemId,List<String> phones) throws Exception{
        Criteria criteria = Criteria.where("userId").is(userId);
        Integer pageSize = 10;
        Integer startRows = (pageNum - 1) * pageSize;
        if(buyerNick != null && !"".equals(buyerNick)){
            criteria.and("buyerNick").is(buyerNick);
        }
        if(phones != null && phones.size() > 0){
            criteria.and("mobile").in(phoneList);
        }
        if(itemId != null && !"".equals(itemId)){
            criteria.and("orders.numIid").is(itemId);
        }
        Aggregation customerAgg = Aggregation.newAggregation(
                Aggregation.project("buyerNick","payment","num","tid","userId","address","mobile","orders"),
                Aggregation.match(criteria),
                   Aggregation.unwind("orders"),
                Aggregation.group("buyerNick").first("buyerNick").as("buyerNick").first("mobile").as("mobile").
                first("address").as("address").sum("payment").as("totalPayment").sum("num").as("itemNum").count().as("orderNum"),
                Aggregation.sort(new Sort(new Sort.Order(Sort.Direction.DESC, "totalPayment"))),
                Aggregation.skip(startRows),
                Aggregation.limit(pageSize)
                );
        List<CustomerDetail> customerList = tradeRepository.findAggregateList(new Query(criteria), userId, customerAgg,CustomerDetail.class);
        return customerList;
    }
    
    public <T> List<T> findAggregateList(Query query,String userNickName, Aggregation aggregation,Class<T> clazz) {
        AggregationResults<T> aggregate = this.mongoTemplate.aggregate(aggregation, collectionName, clazz);
        List<T> customerDetails = aggregate.getMappedResults();
        return customerDetails;
    }
    

    Trade表:

    public class TradeInfo{
        private String tid;//订单id
        private Double payment;//支付金额
        private String buyerNick;//买家昵称
        private String address;//地址
        private String mobile;//手机号
        private Long num;//购买商品数量
        private List<order> orders;子订单
    }
    

    CustomerDetail:

    public class CustomerDetail{
        private String buyerNick;//买家昵称
        private Double totalPayment;//订单金额
        private Integer orderNum;//订单数
        private Integer itemNum;//商品数
        private String address;//地址
    }
    

    聚合分组,先过滤字段为type=Constants.DataSetOpt.OPT_VIEW,通过dateSetId进行分组,并计算每组的个数,.first是需要显示的字段。

        //浏览分组
        private List<Document> flowGroup() {
            Criteria criteria = Criteria.where("type").is(Constants.DataSetOpt.OPT_VIEW);
            Aggregation agg = Aggregation.newAggregation(
                    Aggregation.match(criteria),
                    Aggregation.group("dataSetId")
                            .first("dataSetId").as("dataSetId")
                            .count()
                            .as("dataSetIdCount")
                            .first("dataSetType").as("dataSetType")
    
            );
            AggregationResults<Document> result = mongoTemplate.aggregate(agg,Access.class ,Document.class);
            return result.getMappedResults();
        }
    
    

    也可以使用TypedAggregation的方式进行聚合分组,如下:

        @Test
        public void statTest(){
            TypedAggregation<Statistics> agg = Aggregation.newAggregation(Statistics.class,
                    Aggregation.group("month")
                            .sum("totalVisit")
                            .as("sumTotalVisit")
                            .sum("totalDownload")
                            .as("sumTotalDownload"));
            AggregationResults<Document> result = mongoTemplate.aggregate(agg, Document.class);
    
    //        return result.getMappedResults();
            result.getMappedResults().forEach(document -> System.out.println(document));
        }
    
    

    相关文章

      网友评论

        本文标题:使用mongoTemplate进行Aggregation聚合查询

        本文链接:https://www.haomeiwen.com/subject/dmxrbqtx.html