方法一:循环遍历
let obj1 = {name:'a',age:18};
let obj2 = {name:'b',gender:'man'};
let obj3 = {};
for(var attr in obj1){
obj3[attr] = obj1[attr];
}
for(var attr in obj2){
obj3[attr] = obj2[attr];
}
console.log(obj3);//{name: "b", age: 18, gender: "man"}
方法二:assign
let obj1 = {name:'a',age:18};
let obj2 = {name:'b',gender:'man'};
let obj3 = {};
Object.assign(obj3,obj1,obj2);
console.log(obj3);//{name: "b", age: 18, gender: "man"}
方法三:ES7的对象的拓展运算和ES6的解构赋值
let obj1 = {name:'a',age:18};
let obj2 = {name:'b',gender:'man'};
let obj3 = {...obj1,...obj2};
console.log(obj3);//{name: "b", age: 18, gender: "man"}
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