【编程练习】2个线程A，B（A只能打印奇数，B只能打印偶数）分别

package jayxigua.coding.zfb._20180513;

public class MultiThreadPrint {

    public final static Integer MAX = 100;
    public static int global = 0;

    /**
     * 问题描述：2个线程A，B（A只能打印单数，B只能打印双数）分别按照整体顺序打印1，2，3，4...99，100 
     * 技术点：多线程，同步控制，易扩展（例如需要支持3,4个线程时）
     * 难度：★★★☆
     * 
     * @author jayxigua
     *
     */
    public static void main(String[] args) {
        // TODO Auto-generated method stub

//      new Thread(new MyThread(-2, 3)).start();
//      new Thread(new MyThread(-1, 3)).start();
//      new Thread(new MyThread(0, 3)).start();
        
        new Thread(new MyThread(-1, 2)).start();
        new Thread(new MyThread(0, 2)).start();

    }

}

class MyThread implements Runnable {

    int value;
    int offset;

    public MyThread(int value, int offset) {
        super();
        this.value = value;
        this.offset = offset;
    }

    public int getValue() {
        return value;
    }

    public void setValue(int value) {
        this.value = value;
    }

    public int getOffset() {
        return offset;
    }

    public void setOffset(int offset) {
        this.offset = offset;
    }

    @Override
    public void run() {
        // TODO Auto-generated method stub
        while (value + offset <= MultiThreadPrint.MAX) {

            // System.out.println("[debug] 线程名 " + Thread.currentThread().getName() + "value
            // =" + value + ", global =" + MultiThreadPrint.global);
            synchronized (MultiThreadPrint.MAX) {
                if (value + offset == MultiThreadPrint.global + 1) {

                    value = value + offset;
                    MultiThreadPrint.global = value;
                    System.out.println("线程名 " + Thread.currentThread().getName() + "，打印值 " + value);
                } else {

                }
                try {
                    Thread.sleep(10);
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
        }
    }

}