<div class="image-package"><img src="https://img.haomeiwen.com/i1648392/a6bdd0072b67ac35.jpg" contenteditable="false" img-data="{"format":"jpeg","size":190512,"height":900,"width":1600}" class="uploaded-img" style="min-height:200px;min-width:200px;" width="auto" height="auto"/>
</div><blockquote><p>句子 是一个单词列表,列表中的单词之间用单个空格隔开,且不存在前导或尾随空格。每个单词仅由大小写英文字母组成(不含标点符号)。
例如,"Hello World"、"HELLO" 和 "hello world hello world" 都是句子。
给你一个句子 s 和一个整数 k ,请你将 s 截断 ,使截断后的句子仅含 前 k 个单词。返回 截断 s 后得到的句子。
示例 1:
输入:s = "Hello how are you Contestant", k = 4
输出:"Hello how are you"
解释:
s 中的单词为 ["Hello", "how" "are", "you", "Contestant"]
前 4 个单词为 ["Hello", "how", "are", "you"]
因此,应当返回 "Hello how are you"
示例 2:
输入:s = "What is the solution to this problem", k = 4
输出:"What is the solution"
解释:
s 中的单词为 ["What", "is" "the", "solution", "to", "this", "problem"]
前 4 个单词为 ["What", "is", "the", "solution"]
因此,应当返回 "What is the solution"
示例 3:
输入:s = "chopper is not a tanuki", k = 5
输出:"chopper is not a tanuki"
提示:
1 <= s.length <= 500
k 的取值范围是 [1, s 中单词的数目]
s 仅由大小写英文字母和空格组成
s 中的单词之间由单个空格隔开
不存在前导或尾随空格
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/truncate-sentence
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。</p></blockquote><h1 id="18lbk">题解</h1><div class="image-package"><img src="https://img.haomeiwen.com/i1648392/92d5f1be7738abba.jpg" contenteditable="false" img-data="{"format":"jpeg","size":67005,"height":830,"width":1314}" class="uploaded-img" style="min-height:200px;min-width:200px;" width="auto" height="auto"/>
</div><h2 id="uih9u">Swift</h2><blockquote><p><b/><span style="font-size: 14px; font-family: -apple-system, BlinkMacSystemFont, "Segoe UI", "PingFang SC", "Hiragino Sans GB", "Microsoft YaHei", "Helvetica Neue", Helvetica, Arial, sans-serif, "Apple Color Emoji", "Segoe UI Emoji", "Segoe UI Symbol";">class Solution {</span></p> func truncateSentence(_ s: String, _ k: Int) -> String {
//1 分割
//2 数组截取
//3 重组
return s.split(separator: " ")[0 ..< k].joined(separator: " ")
}
}
print(Solution().truncateSentence("Hello how are you Contestant", 4))
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