Swift相比于Objective-C又一个重要的优点,它对函数式编程提供了很好的支持,Swift提供了map、filter、reduce这三个高阶函数作为对容器的支持。
1 map:可以对数组中的每一个元素做一次处理
let stringArray = ["Objective-C", "Swift", "HTML", "CSS", "JavaScript"]
//1.先定义返回字符串个数的方法,再map
func stringCount(string: String) -> Int {
return string.count
}
let count = stringArray.map(stringCount)
Tprint(messsage: count)//[11, 5, 4, 3, 10]
//2.直接使用map方法
let count1 = stringArray.map{ (string) -> Int in
return string.count
}
Tprint(messsage: count1)//[11, 5, 4, 3, 10]
// 3.$0代表数组中的每一个元素
let count2 = stringArray.map{
return $0.count
}
Tprint(messsage: count2)//[11, 5, 4, 3, 10]
2 flatMap与map不同之处:
(1)flatMap返回后的数组中不存在nil,同时它会把Optional解包
let count3 = stringArray.map { (str) -> Int? in
return str.count
}
Tprint(messsage: count3)//[Optional(11), Optional(5), Optional(4), Optional(3), Optional(10)]
let count4 = stringArray.flatMap { (str) -> Int? in
return str.count
}
Tprint(messsage: count4)//[11, 5, 4, 3, 10]
(2)flatMap还能把数组中存有数组的数组(二维数组、N维数组)一同打开变成一个新的数组
let array = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
let arr1 = array.map{ $0 }
arr1 // [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
let arr2 = array.flatMap{ $0 }
arr2 // [1, 2, 3, 4, 5, 6, 7, 8, 9]
(3)flatMap也能把两个不同的数组合并成一个数组,这个合并的数组元素个数是前面两个数组元素个数的乘积
let fruits = ["Apple", "Orange", "Puple"]
let counts = [2, 3, 5]
let array = counts.flatMap { count in
fruits.map ({ fruit in
return fruit + " \(count)"
})
}
array // ["Apple 2", "Orange 2", "Puple 2", "Apple 3", "Orange 3", "Puple 3", "Apple 5", "Orange 5", "Puple 5"]
3 filter:过滤,可以对数组中的元素按照某种规则进行一次过滤
let stringArray = ["Objective-C", "Swift", "HTML", "CSS", "JavaScript"]
// 筛选出字符串的长度小于10的字符串
func stringCountLessThan10(str :String) -> Bool{
return str.count < 10
}
let count5 = stringArray.filter(stringCountLessThan10(str:))
Tprint(messsage: count5)
let count6 = stringArray.filter { (str) -> Bool in
return str.count < 10
}
Tprint(messsage: count6)
let count7 = stringArray.filter { $0.count < 10}
Tprint(messsage: count7)
4 reduce:计算,可以对数组的元素进行计算
// 将数组中的每个字符串用‘、’拼接
let stringArray = ["Objective-C", "Swift", "HTML", "CSS", "JavaScript"]
func appendString(string1: String, string2: String) -> String {
return string1 == "" ? string2 : string1 + "、" + string2
}
// reduce方法中的第一个参数是初始值
stringArray.reduce("", appendString)
stringArray.reduce("", {(string1, string2) -> String in
return string1 == "" ? string2 : string1 + "、" + string2
})
// $0表示计算后的结果, $1表示数组中的每一个元素
stringArray.reduce("", {
return $0 == "" ? $1 : $0 + "、" + $1
})
好啦,介绍完了愿能与君共勉。
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