美文网首页
swift (循环与选择)

swift (循环与选择)

作者: cyhai | 来源:发表于2019-08-27 09:41 被阅读0次
for in 正序
 for i in (0...10){
            
            print("循环循序:",i)
        }
        
 let arr = ["01","02","03","04","05"]
        
        for  str:String in arr {
            print("for循环:\(str)")
        }
for in 倒序
for i in (0...10).reversed() {
            
            print("循环倒序:",i)
        }
        
for in 获取元素与下标
//正序
let arr = ["字符串01","字符串02","字符串03","字符串04"];
        for (index,str) in arr.enumerated() {
            print("下标:\(index)----元素:\(str)")
        }

//倒序
for (index,str) in arr.enumerated().reversed() {
            print("下标:\(index)----元素:\(str)")
        }
while
var i = 0;
        while i < 10 {
            print("while循环\(i)")
            i = i + 1;
        }
if
 func ifTest(istrue:Bool) -> Void {
        
        if istrue == true {
            print("这是真")
        }
        else
        {
            print("这是假")
        }
        
    }  
switch
 func switchTest(index:NSInteger) -> Void {
        
        switch index {
        case 100:
            let newIndex = index + 1;
            print("新下标:",newIndex)
            break;
        case 200:
            let newIndex = index + 1;
            print("新下标2:",newIndex)
            break;
        default:
            break;
        }
    }

相关文章

网友评论

      本文标题:swift (循环与选择)

      本文链接:https://www.haomeiwen.com/subject/fgrsectx.html