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Servlet + Ajax简单demo

Servlet + Ajax简单demo

作者: 野狗子嗷嗷嗷 | 来源:发表于2017-05-21 10:40 被阅读86次

    GET

    AjaxServlet.java

    @WebServlet("/ajax")
    public class AjaxServlet extends HttpServlet {
        public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
            doPost(request, response);
        }
    
        public void doPost(HttpServletRequest request, HttpServletResponse response) throws  ServletException, IOException {
            response.setContentType("text/html;charset=UTF-8" );
            PrintWriter out = response.getWriter();
            String old = request.getParameter("username" );
            if  (old ==  null  || old.length() ==  0 ) {
                out.println("用户名不能为空" );
            } else  {
                if  (old.equals( "admin" )) {
                    out.println("用户名 ["  + old +  "] 已经存在,请使用其他用户名" );
                } else  {
                    out.println("用户名 ["  + old +  "] 尚未存在,可以使用该用户名注册" );
                }
            }
        }
    }
    

    ajax.html

    <html>
    <head>
        <title>ajax</title>
        <script src="https://code.jquery.com/jquery-3.2.1.min.js"></script>
    </head>
    
    <body>
    <input type="text" id="username"/>
    <input type="button" value="11" onclick="verify();"/>
    <div id="result"></div>
    </body>
    
    <script>
        function verify(){
            var jqueryObj = $("#username");
            var username = jqueryObj.val();
            $.get("/ajax?username=" + username, null, callback);
        }
        function callback(data){
            $("#result").html(data);
        }
    </script>
    </html>
    

    POST

    LoginServlet.java

    @WebServlet("/login")
    public class LoginServlet extends HttpServlet {
        public static final String DBDRIVER = "com.mysql.jdbc.Driver";
        public static final String DBURL = "jdbc:mysql://localhost:3306/login?useSSL=false";
        public static final String DBUSER = "root";
        public static final String DBPASS = "123";
        boolean flag = false;
        String username = null;
    
        protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
            Connection conn = null;  //数据库连接
            PreparedStatement pstmt = null;    //数据库预处理操作
            ResultSet rs = null;    //查询要处理结果集
    
            try{
                Class.forName(DBDRIVER);
                conn = DriverManager.getConnection(DBURL,DBUSER,DBPASS);
    
                String sql = "select username from user where username = ? and password = ?";
                pstmt = conn.prepareStatement(sql);
                pstmt.setString(1, request.getParameter("username"));
                pstmt.setString(2, request.getParameter("password"));
    
                rs = pstmt.executeQuery();
                if(rs.next()){          //如果有数据就执行
                    flag = true;        //表示登陆成功
                    username = rs.getString(1);
                }
                System.out.println(username);
            } catch (Exception e){
                e.printStackTrace();
            } finally{
                try{
                    rs.close();
                    pstmt.close();
                    conn.close();
                }catch(Exception e){
                    e.printStackTrace();
                }
            }
    
            response.setContentType("text/html; charset=UTF-8");
            PrintWriter out=response.getWriter();
            if(flag == true) {
                out.println("success");
            } else {
                out.print("error");
            }
            out.flush();
            out.close();
        }
    
        protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
            doPost(request,response);
        }
    }
    

    login.html

    <!DOCTYPE html>
    <html lang="en">
    <head>
        <meta charset="UTF-8">
        <title>Ajax</title>
        <script src="https://code.jquery.com/jquery-3.2.1.min.js"></script>
    </head>
    <body>
    
    <form action='/login' id='addForm' type='post'>
        用户名:<input type='text' id='username' name="username" value=""><br>
        密码:<input type='password' id='password' name="password" value=""><br>
        <input type='button' value='提交' onclick='login()'>
    </form>
    <label id="msg"></label>
    </body>
    
    <script type="text/javascript">
        function login(){
            var user = {
                username:"admin",
                password:"123456"
            };
            var username = $('#username').val();
            var password = $('#password').val();
            if ("" == name || "" == pwd) {
                alert('用户名或者密码不能为空');
            } else {
                $.ajax({
                    url: 'http://localhost:8080/login?username=' + username + '&password=' + password,
                    type: 'post',
                    success: function (data) {
                        if('success' == data) {
                            // location.href='<%=basePath%>/index.jsp'
                            window.location.reload();
                        } else {
                            $('#msg').html(msg);
                        }
                    }
    
                })
            }
        }
    
        function login2(){
            $.ajax({
                url: 'http://localhost:8080/login',        // 不能在末尾再加一个/,不然出现404
                data: $('#addForm').serialize(),
                type: 'post',
                contentType: 'application/x-www-form-urlencoded; charset=UTF-8',    //防止乱码
                success:function(data){
                    console.log('添加成功');
                    console.log(data);
                }
            })
        }
    </script>
    </html>
    

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