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2.1.1、数据类型练习

2.1.1、数据类型练习

作者: 艾希_可可 | 来源:发表于2017-06-28 09:57 被阅读11次

    //: Playground - noun: a place where people can play

    importUIKit

    //1、var string="my name is Tina"将string按字母顺序排序

    varstring="my name is Tina"

    //let stringArray = string.characters.sorted {$0 < $1}

    //print(stringArray)

    //var stringRange = ""

    //for character in stringArray

    //{

    //stringRange.append(character)

    //}

    //print(stringRange)

    //print(string)

    vararrayStrs:Array = []

    for(index,char)instring.characters.enumerated() {

    arrayStrs.append(String(char))

    }

    print(arrayStrs)

    letcmp:(_a:String,_b:String) ->Int= {

    (a,b)in

    letx = a.compare(b)

    ifx == .orderedAscending{//升序

    return-1

    }elseifx == .orderedSame{//相同

    return0

    }else{

    return1

    }

    }

    cmp("b","a")

    foriin1..

    forjin0..

    ifcmp(arrayStrs[j],arrayStrs[j+1]) ==1{

    lettemp =arrayStrs[j]

    arrayStrs[j] =arrayStrs[j+1]

    arrayStrs[j+1] = temp

    }

    }

    }

    varnewResult:String=""

    foriinarrayStrs{

    newResult+=i

    }

    print(arrayStrs,newResult)

    //2、var bigArray=[4,6,1,3,2,5]进行排序,用三种方法

    varresultArray = [String]()

    varbigArray=[4,6,1,3,2,5]

    //bigArray.sort()

    foriin1..

    {

    forjin0..< (bigArray.count- i)

    {

    ifbigArray[j] >bigArray[j +1]

    {

    swap(&bigArray[j], &bigArray[j +1])

    //let temp = bigArray[j]

    //bigArray[j] = bigArray[j + 1]

    //bigArray[j + 1] = temp

    }

    }

    }

    print(bigArray)

    //3、写一个九九乘法表

    /*

    1 * 1 = 1

    1 * 2 = 22 * 2 = 4

    1 * 3 = 32 * 3 = 63 * 3 = 9

    1 * 4 = 42 * 4 = 83 * 4 = 124 * 4 = 16

    1 * 5 = 52 * 5 = 103 * 5 = 154 * 5 = 205 * 5 = 25

    1 * 6 = 62 * 6 = 123 * 6 = 184 * 6 = 245 * 6 = 306 * 6 = 36

    1 * 7 = 72 * 7 = 143 * 7 = 214 * 7 = 285 * 7 = 356 * 7 = 427 * 7 = 49

    1 * 8 = 82 * 8 = 163 * 8 = 244 * 8 = 325 * 8 = 406 * 8 = 487 * 8 = 568 * 8 = 64

    1 * 9 = 92 * 9 = 183 * 9 = 274 * 9 = 365 * 9 = 456 * 9 = 547 * 9 = 638 * 9 = 729 * 9 = 81

    */

    foriin1...9{

    forjin1...9{//j代表列,i代表行

    //print("\(i)*\(j)=\(i*j) ",terminator:"")

    ifi>=j {

    print("\(j)*\(i)=\(i*j) ",terminator:"")

    }

    ifj ==9{

    print("\n")

    }

    }

    }

    //var num = 1

    ////result为结果

    //var result = ""

    ////外循环循环9次row为行数

    //for row in 1...9{

    ////tmp临时存放结果,外循环执行一次重置一次tmp

    //var tmp = ""

    ////内循环循环num次

    //for row in 1..

    //tmp = tmp + "\(row)*\(num)=\(row*num)\t"

    //

    //}

    ////拼接结果

    //result =tmp + "\(row)*\(num)=\(row*num)"

    //print(result)

    ////外循环执行一次需要出现结果的个数+1

    //num += 1

    //}

    //4、编写一个函数可以计算其参数的平均值

    funcaverage(a:Double...) ->Any{

    varsum:Double=0

    foraina{

    sum += a

    }

    returnsum /Double(a.count)

    }

    average(a:1,2,3,4,5,6)

    //5、定义一个数组,写一个函数,传任意数组中的两个元素,可以实现交换数组中的两个元素

    vararray = [5,4,3,2,1,0]

    swap(&array[0], &array[4])

    funcexchangeData(array:Array, a:Int, b:Int) ->Array{

    vararray = array

    letdata = array[a]

    array[a] = array[b]

    array[b] = data

    returnarray

    }

    exchangeData(array:array, a:4, b:0)

    varoldArray = [5,4,3,2,1,0]

    funcjiaohuan (array:Array, a:Int, b:Int) -> (Array){

    varneArray = array

    swap(&neArray[a],&neArray[b])

    returnneArray

    }

    varanswer:Array=jiaohuan(array:oldArray, a:0, b:5)

    funcswapData(_nums:inout[Int],_p:Int,_q:Int) {

    lettemp = nums[p]

    nums[p] = nums[q]

    nums[q] = temp

    }

    swapData(&oldArray,5,0)

    funcswap2(_nums:inout[T],_p:Int,_q:Int) {

    (nums[p], nums[q]) = (nums[q], nums[p])

    }

    swap2(&oldArray,1,3)

    //6、将数组[“A”,”B”,”C”]转换为字符串A:B:C

    lettimu = ["A","B","C"]

    //let zhuanhuan = timu.joined(separator: ":")

    vars =""

    foriintimu{

    ifi !="C"{

    s+=String("\(i):")

    }else{

    s+=String("\(i)")

    }

    }

    print(s)

    //6、将课堂上讲的朋友圈的三个数组(用了字典、元组、数组),用所学到的知识,单独获取到“小程序”这个字符串值

    //元组

    letdataArray1 = [[(image:"0",name:"朋友圈")],[(image:"1",name:"扫一扫"),(image:"2",name:"摇一摇")],[(image:"3",name:"附近的人"),(image:"4",name:"漂流瓶")],[(image:"5",name:"购物"),(image:"6",name:"游戏")],[(image:"7",name:"小程序")]]

    letoneSection1 =dataArray1[4]

    letoneRow1 =oneSection1[0]

    letstring1 =oneRow1.name

    print(string1)

    //数组

    letdataArray2 = [[["0","朋友圈"]],[["1","扫一扫"],["2","摇一摇"]],[["3","附近的人"],["4","漂流瓶"]],[["5","购物"],["6","游戏"]],[["7","小程序"]]]

    letoneSection2 =dataArray2[4]

    letoneRow2 =oneSection2[0]

    letstring2 =oneRow2[1]

    print(string2)

    //字典

    letdataArray3 = [[["image":"0","name":"朋友圈"]],[["image":"1","name":"扫一扫"],["image":"2","name":"摇一摇"]],[["image":"3","name":"附近的人"],["image":"4","name":"漂流瓶"]],[["image":"5","name":"购物"],["image":"6","name":"游戏"]],[["image":"7","name":"小程序"]]]

    letoneSection3 =dataArray3[4]

    letoneRow3 =oneSection3[0]

    letstring3 =oneRow3["name"]

    print(string3??"name值不存在")

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