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swift 高阶函数使用

swift 高阶函数使用

作者: 恬甜咖啡糖_0301 | 来源:发表于2021-07-01 19:11 被阅读0次

    sort , forEach, filter, first(where:), last(where:) removeAll(where:), allSatisfy, map, reduce

    // MARK: sort
    func testSort() {
        var array1 = ["Animal", "Baby", "Apple", "Google", "Aunt"]
        array1.sort()
        let array2 = ["Animal", "Baby", "Apple", "Google", "Aunt"]
        array2.sorted()
    
        /**
         1. 默认是升序
         2. sorted 返回一个新的集合
         3. sort 直接在原来的集合上操作
         */
    
        //降序
        array1.sort() { (str1, str2) in
            return str1 > str2 // 9times
        }
        array2.sorted() { (str1, str2) in
            return str1 > str2
        }
    
        //降序 简写
        array1.sort { return $0 > $1 } // 10times
        array2.sorted { return $0 > $1 }
    }
    
    // MARK: forEach
    func testForEach() {
        let array1 = ["Animal", "Baby", "Apple", "Google", "Aunt"]
        array1.forEach { str in print(str) }
        array1.forEach { print($0) }
    }
    
    
    // MARK: filter & first(where:) & last(where:) & removeAll(where:)
    func testFilter() {
        var array1 = ["Animal", "Baby", "Apple", "Google", "Aunt"]
        /**
         筛选里面的闭包必须返回Bool, 筛选出返回true的元素
         */
        array1.filter { str in
            str.hasPrefix("A")
        }.forEach{ print($0) }
    
        array1.filter { $0.hasPrefix("A") }.forEach{ print($0) }
        
        // 筛选出第一个符合条件的元素
        let ele1 = array1.first { $0.hasPrefix("G") }
        ele1
        // 筛选出随后一个符合条件的元素
        let ele2 = array1.last { $0.hasPrefix("B") }
        ele2
        //删除符合条件的元素
        array1.removeAll { $0.hasPrefix("A") }
        array1
    }
    
    // MARK: allSatisfy
    func testAllSatisfy() {
        /**
         检查序列中所有元素是否满足条件,全部满足才返回true
         */
        let scores = [86, 88, 95, 90]
        let passed = scores.allSatisfy {
            $0 > 80
        }
        passed
    }
    
    // MARK: map & compactMap & mapValues & compactMapValues
    func testMap() {
        /**
         闭包返回一个变换后的元素,所有变换后的元素组成一个新的集合
         */
        let newStr = "test".map { "\($0) - new" }
        newStr
    
        let array3 = ["array1","array2","array3","array4","array5"]
        let array3New = array3.map { "\($0)-new" }
        array3 // ["array1", "array2", "array3", "array4", "array5"]
        array3New // ["array1-new", "array2-new", "array3-new", "array4-new", "array5-new"]
    
        let dic = ["key1": "value1"]
        let dicNew = dic.map { ["\($0.key)-new" : "\($0.value)-new"] }
        dic // ["key1": "value1"]
        dicNew // [["key1-new": "value1-new"]]
    
        /**
         compactMap 可以过滤掉空元素
         compactMap(flatMap 被废弃了) 可以过滤掉空元素,
         */
        let array4 = ["array1","array2", nil ,"array4","array5"]
        let list1 = array4.map { $0 }
        list1 // ["array1", "array2", nil, "array4", "array5"]
        let list2 = array4.compactMap { $0 }
        list2 // "array1", "array2", "array4", "array5"]
    
        /**
         mapValues & compactMapValues 专门用于字典
         */
        let dic1 = ["1": "1", "2": "2", "3": "3", "4": "r", "5": "5"]
        /**
         mapValues类似数组中的map,只是专门针对字典的values, mapValues 返回的还是一个字典
         如果在字典上用map,返回的是数组(key/value)
         
         compactMapValues 类似数组中的compactMap,过滤掉不符合条件的内容,只是专门针对字典的values, compactMapValues 返回的还是一个字典
         如果在字典上用compactMap,返回的是数组(key/value)
         */
        let result1 = dic1.mapValues { Int($0)}
        result1 // ["4": nil, "5": 5, "3": 3, "1": 1, "2": 2]
        let result2 = dic1.map { Int($0.value)} // [nil, 5, 3, 1, 2]
        result2
        let result3 = dic1.compactMapValues { Int($0) } // ["2": 2, "1": 1, "3": 3, "5": 5]
        result3
        let result4 = dic1.compactMap { Int($0.value) } // [5, 2, 3, 1]
        result4
    }
    
    // MARK: reduce 把多个元素的值合并为一个新的值
    func testReduce() {
        
        let sum = [1, 3, 3, 4]
        let start = 102
        
        /**
         可以把多个元素的值合并成一个新的值
         start: 设置初始状态
         result: 中间结果
         num: 集合中的每个元素
         */
        //直接返回结果
        let total = sum.reduce(start) { result, num -> Int in
            print("result \(result); num \(num)")
            return result+num
        }
        total // 113
        
        //不返回结果
        var into = 102
        let total2 = sum.reduce(into: into) { result, num in
            print("result \(result); num \(num)")
            into += num
            print("into \(into)")
        }
        into // 113
        total2 // 102
        
        //简写1
        let total3 = sum.reduce(start) { $0 + $1}
        total3 // 113
        
        //简写2
        let total4 = sum.reduce(start, +)
        total4 // 113
        
        //字符串 reduce
        let total5 = ["a","b","c"].reduce("1", { $0 + ", " + $1})
        total5 // "1, a, b, c"
        
        let dic = ["1": "value1", "2": "value2", "3": "value3", "4": "valuer", "5": "value5"]
        let reduceResult = dic.reduce("======") { (result, item: (key: String, value: String)) -> String in
            result + item.value
        }
        reduceResult // "======value2value3value5value1valuer"
        
    }
    //testReduce()
    
    // MARK: 组合方法
    func comminMethod() {
        let array1 = ["Animal", "Baby", "Apple", "Google", "Aunt"]
        array1
            .sorted{ $0 > $1}
            .filter { $0.hasPrefix("A")}
            .forEach { print($0) }
    }
    comminMethod()
    

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