public boolean PowerOfK(int num){
return (num>0)&&(num==1||(num%k==0&&PowerOfK(num/k)));
}
public boolean PowerOfK(int num){
return (num>0)&&(num==1||(num%k==0&&PowerOfK(num/k)));
}
本文标题:Leetcode power of k 的一般解法
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