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MySQL查询今天、昨天、7天、近30天、本月、上一月 数据

MySQL查询今天、昨天、7天、近30天、本月、上一月 数据

作者: 土豹子123 | 来源:发表于2017-11-24 14:44 被阅读22次

    今天

    select * from 表名 where to_days(时间字段名) = to_days(now());

    昨天

    SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1

    7天

    SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)

    近30天

    SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)

    本月

    SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )

    上一月

    SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1

    #查询本季度数据

    select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());

    #查询上季度数据

    select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));

    #查询本年数据

    select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());

    #查询上年数据

    select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));

    查询当前这周的数据

    SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());

    查询上周的数据

    SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;

    查询当前月份的数据

    select name,submittime from enterprise   where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')

    查询距离当前现在6个月的数据

    select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();

    查询上个月的数据

    select name,submittime from enterprise   where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')

    select*from`user`whereDATE_FORMAT(pudate,'%Y%m')=DATE_FORMAT(CURDATE(),'%Y%m') ;

    select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())

    select*

    from user

    where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' ))=MONTH (now())

    select*

    from [ user ]

    where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' ))=YEAR (now())

    andMONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' ))=MONTH (now())

    select*

    from [ user ]

    where pudatebetween上月最后一天

    and下月第一天

    where   date(regdate)   =   curdate();

    select   *   from   test   where   year(regdate)=year(now())   and   month(regdate)=month(now())   and   day(regdate)=day(now())

    SELECT date( c_instime ) ,curdate( )

    FROM `t_score`

    WHERE 1

    LIMIT 0 , 30

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