Python Challenge[4]

[Level 4]

Title: follow the chain

页面中无有用的提示，查看源码，在注释中找到

urllib may help. DON'T TRY ALL NOTHINGS, since it will never end. 400 times is more than enough.

且图片是一个链接，点击图片，跳转到http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=12345，网页显示and the next nothing is 44827。可以想到是修改url中的nothing值直至找到答案。

import urllib.request,re
url = 'http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing='
num = '12345'
pattern = re.compile(r'.*and the next nothing is (\d+)')
while num:
  data = urllib.request.urlopen(url+num).read().decode('utf-8')
  num = ''.join(pattern.findall(data))
  print(data)

运行结束，显示Yes. Divide by two and keep going.，此时的num=16044，num=num/2=8022，修改后继续运行while循环（中间出现过一个干扰项），得到最终结果是peak.html，[Level 5]

实际中使用urllib.request.urlopen()处理速度较慢，且经常死，换用第三方库（如httplib2）效果大赞。

import httplib2
data = httplib2.Http().request(url+num)[1].decode('utf-8')

httplib2.Http().request()返回Response实例和内容组成的元组。

Python Challenge Wiki

获取nothing值和其他方法：

text.strip().split()[-1]

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