Problem

https://uva.onlinejudge.org/external/104/10474.pdf

Solution

#include<iostream>
#define MAX_NUM 10005 // 最大數字為10000
using namespace std;

int main()
{    
    int N,Q,case_num = 0;

    //若N和Q為0結束
    while((cin >> N >> Q) && N && Q)
    {
        
        //用陣列計數所有的數字個數
        int count[MAX_NUM] = {0};
        for(int i = 0 ; i < N ; i++)
        {
            int temp;
            cin >> temp;
            count[temp]++;
        }
        
        cout << "CASE# " << ++case_num << ":" << endl;
        for(int i = 0 ; i < Q ; i++)
        {
            int ask_num;
            cin >> ask_num;
            
            int ans = 0;
            //如果數字個數為0個則為not found
            if(count[ask_num] == 0)
                cout << ask_num << " not found" << endl;
            else
            {
                //計數到前一個數字的總數
                for(int j = 0 ; j != ask_num ; j++)
                    ans += count[j];
                //下一個數字的第一個所以要加1
                ans++;
                cout << ask_num << " found at " << ans << endl;
            }
        
        }//end of for i
    
    }//end of while
    return 0;
}