LeetCode 1108. Defanging an IP A

Given a valid (IPv4) IP address, return a defanged version of that IP address.

A defanged IP address replaces every period "." with "[.]".

Example 1:

Input: address = "1.1.1.1"
Output: "1[.]1[.]1[.]1"

Example 2:
Input: address = "255.100.50.0"
Output: "255[.]100[.]50[.]0"

Constraints:
The given address is a valid IPv4 address.

Solution1:

class Solution:
    def defangIPaddr(self, address: str) -> str:
        res = []
        for i in address:
            if i == ".":
                res.append("[.]")
            else:
                res.append(i)
        return "".join(res)

Solution2
class Solution:
def defangIPaddr(self, address: str) -> str:
return address.replace(".", "[.]")

Explanation:
Both two solutions are quite self-explaining. The 2nd one uses the in-built function so just uses one line.