传入一个文件夹路径,通过os模块遍历出文件夹下所有apk,然后为每一个apk开启一个反编译的线程,通过调用shell命令apktool反编译apk,然后re匹配渠道包,放入一个list中。最后,递归延迟检查如果apk数量和渠道号数量相同,那么程序结束,打印出所有渠道号。
ps:apktool和.py文件要在同一个目录下
#_*_ coding:utf-8 _*_
'''
作者:cloudhuan
blog:http://blog.csdn.net/cloud_huan
'''
import os,sys,re
import thread,threading
import shutil
import time
########################################################################
class CheckChannel():
""""""
#----------------------------------------------------------------------
list_channel = []
def __init__(self,apkDir = '/home/cloudhuan/桌面/tmp'):
"""Constructor"""
self.apkDir = apkDir
def check(self):
self.listDir = os.listdir(self.apkDir)
for apk in self.listDir:
CheckThread(apk, self.apkDir,self.list_channel).start()
self.pp()
def pp(self):
if len(self.list_channel) == len(self.listDir):
print "渠道号共有这么多个:",len(self.list_channel)
for i in self.list_channel:
print i
else:
time.sleep(5)
self.pp()
########################################################################
class CheckThread(threading.Thread):
""""""
#----------------------------------------------------------------------
def __init__(self,apk,apkDir,list_channel):
"""Constructor"""
threading.Thread.__init__(self)
self.apk = apk
self.apkDir = apkDir
self.list_channel = list_channel
def run(self):
apk_name = os.path.splitext(self.apk)[0]
apk_in_path = os.path.join(self.apkDir,self.apk)
apk_out_path = os.path.join(self.apkDir,apk_name)
cmd = 'java -jar apktool.jar d -f -s %s %s'%(apk_in_path,apk_out_path)
os.popen(cmd)
manifest_path = os.path.join(apk_out_path,'AndroidManifest.xml')
if manifest_path == None:
raise IOError
with open(manifest_path,'r') as f:
m_result = f.read()
#re正则匹配的渠道key,不同apk可能不一样,这里是InstallChannel,有的是umeng_channel
pattern = re.compile(r'<meta-data android:name="%s" android:value="(\w+)"'%'InstallChannel')
self.list_channel.append(pattern.findall(m_result)[0])
shutil.rmtree(apk_out_path)
if __name__ == '__main__':
#实例化CheckChannel对象传入路径,默认是我的测试路径,如CheckChannel('c:/user/cloudhuan/test')
CheckChannel().check()
原文:https://blog.csdn.net/Cloud_Huan/article/details/50833652?utm_source=copy
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