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367. Valid Perfect Square

367. Valid Perfect Square

作者: Jeanz | 来源:发表于2017-08-25 10:40 被阅读0次

Given a positive integer num, write a function which returns True if num is a perfect square else False.

Note: Do not use any built-in library function such as sqrt.
Example 1:

Input: 16
Returns: True

Example 2:

Input: 14
Returns: False

一刷
解法: binarySearch。

class Solution {
    public boolean isPerfectSquare(int num) {
        int low = 1, high = num;
        while (low <= high) {
            long mid = (low + high) >>> 1;
            if (mid * mid == num) {
                return true;
            } else if (mid * mid < num) {
                low = (int) mid + 1;
            } else {
                high = (int) mid - 1;
            }
        }
        return false;
    }
}

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