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centos-i686执行shellcode

centos-i686执行shellcode

作者: 一路向后 | 来源:发表于2021-02-03 21:55 被阅读0次

    1.源码实现

    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    
    char sc[] = "\x31\xc0"
            "\x50"
            "\x68\x2f\x2f\x73\x68"
            "\x68\x2f\x62\x69\x6e"
            "\x89\xe3"
            "\x50"
            "\x53"
            "\x89\xe1"
            "\x31\xd2"
            "\xb0\x0b"
            "\xcd\x80";
    
    int main()
    {
            void (*fp)(void);
    
            fp = (void *)sc;
    
            fp();
    
            return 0;
    }
    

    2.编译源码

    $ gcc -z execstack -o example example.c
    

    3.运行程序

    $ ./example
    sh-4.1$
    

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