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Leetcode 107. Binary Tree Level

Leetcode 107. Binary Tree Level

作者: SnailTyan | 来源:发表于2018-09-19 19:49 被阅读8次

    文章作者:Tyan
    博客:noahsnail.com  |  CSDN  |  简书

    1. Description

    Binary Tree Level Order Traversal II

    2. Solution

    • Version 1
    /**
     * Definition for a binary tree node.
     * struct TreeNode {
     *     int val;
     *     TreeNode *left;
     *     TreeNode *right;
     *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     * };
     */
    class Solution {
    public:
        vector<vector<int>> levelOrderBottom(TreeNode* root) {
            vector<vector<int>> result;
            if(!root) {
                return result;
            }
            queue<TreeNode*> q;
            q.push(root);
            traverseLevel(q, result);
            reverse(result.begin(), result.end());
            return result;
        }
        
        
    private:
        void traverseLevel(queue<TreeNode*>& q, vector<vector<int>>& result) {
            vector<int> values;
            int size = q.size();
            while(size) {
                TreeNode* current = q.front();
                q.pop();
                if(current) {
                    values.push_back(current->val);
                    if(current->left) {
                        q.push(current->left);
                    }
                    if(current->right) {
                        q.push(current->right);
                    }
                }
                size--;
            }
            result.push_back(values);
            if(!q.empty()) {
                traverseLevel(q, result);
            }
        }
    };
    
    • Version 2
    /**
     * Definition for a binary tree node.
     * struct TreeNode {
     *     int val;
     *     TreeNode *left;
     *     TreeNode *right;
     *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     * };
     */
    class Solution {
    public:
        vector<vector<int>> levelOrderBottom(TreeNode* root) {
            vector<vector<int>> result;
            if(!root) {
                return result;
            }
            depthLevel(result, root, 0);
            reverse(result.begin(), result.end());
            return result;
        }
        
        
    private:
        void depthLevel(vector<vector<int>>& result, TreeNode* root, int depth) {
            if(!root) {
                return;
            }
            depth++;
            if(depth > result.size()) {
                vector<int> values;
                result.emplace_back(values);
            }
            depthLevel(result, root->left, depth);
            depthLevel(result, root->right, depth);
            result[depth - 1].push_back(root->val);
        }
    };
    

    Reference

    1. https://leetcode.com/problems/binary-tree-level-order-traversal-ii/description/

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